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📝 Solve equations with constants on both sides (14 MCQs)

📖 From Digital SAT Algebra • 2. Linear Equations And Inequalities • 14 questions available

What is Solve equations with constants on both sides?

Definition:
Solving equations with constants on both sides means equations where there are numbers (constants) on both the left and right sides, alongside the variable. The goal is to isolate the variable by moving all constant terms to one side using the Addition or Subtraction Property.

Working:
First, move all variable terms to one side (if they are on both sides), then move all constants to the opposite side by adding or subtracting. Finally, divide by the coefficient. For example, solve 2x+5=x32x + 5 = x - 3: subtract xx: x+5=3x + 5 = -3, subtract 5: x=8x = -8.

Example:
Solve 4n+7=2n+154n + 7 = 2n + 15. Subtract 2n2n: 2n+7=152n + 7 = 15, subtract 7: 2n=82n = 8, divide by 2: n=4n = 4. Check: 4(4)+7=16+7=234(4)+7 = 16+7=23, 2(4)+15=8+15=232(4)+15 = 8+15=23.

Reason:
This approach ensures all constant terms are grouped together, simplifying the equation to a standard form ax=bax = b, which is easy to solve.

7
Easy
5
Medium
2
Hard

📝 All Solve equations with constants on both sides MCQs

Q1. A student solves 3x+7=5x33x + 7 = 5x - 3 by subtracting 3x3x from both sides to get 7=2x37 = 2x - 3, then adds 3 to get 10=2x10 = 2x, and finally divides to get x=5x = 5. Which step contains the first error if any?

A.Subtracting 3x3x
B.Adding 3
C.Dividing by 2
D.No error
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: The student's steps are mathematically correct. Subtracting 3x3x isolates the variable term on the right, adding 3 isolates the constant, and dividing by 2 gives x=5x=5. A common misconception is that the order of operations is wrong, but here the inverse operations are applied correctly in sequence.

Q2. Which equation has the same solution as 4x9=2x+74x - 9 = 2x + 7?

A.2x=162x = 16
B.4x=2x+164x = 2x + 16
C.6x=26x = -2
D.x9=7x - 9 = 7
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: The original equation simplifies to 2x=162x = 16 after adding 9 and subtracting 2x2x. Option A is exactly that simplified form. Option B is equivalent but not simplified; option C has incorrect sign; option D ignores the 4x4x term. Recognizing equivalent forms tests understanding of equation transformation.

Q3. A rectangle has perimeter 48 cm. Its length is 2x+52x + 5 cm and its width is x3x - 3 cm. Write and solve an equation to find xx.

A.2(2x+5+x3)=48x=82(2x+5 + x-3)=48 \Rightarrow x=8
B.2x+5+x3=48x=15.332x+5 + x-3 = 48 \Rightarrow x=15.33
C.2(2x+5)+2(x3)=48x=72(2x+5) + 2(x-3)=48 \Rightarrow x=7
D.2(2x+5)+2(x3)=48x=22/32(2x+5)+2(x-3)=48 \Rightarrow x=22/3.
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: The perimeter formula is 2(L+W)=482(L+W)=48. Substituting gives 2(3x+2)=486x+4=486x=44x=7.332(3x+2)=48 \Rightarrow 6x+4=48 \Rightarrow 6x=44 \Rightarrow x=7.33

Q4. Given the equation 73x=4x+147 - 3x = 4x + 14, a student claims x=1x = -1. Is this correct? If not, what is the error?

A.Correct, x=1x=-1
B.Incorrect; should be x=1x=1
C.Incorrect; should be x=3x=-3
D.Incorrect; should be x=3x=3
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: Actually 73(1)=7+3=107 - 3(-1) = 7+3=10 and 4(1)+14=4+14=104(-1)+14 = -4+14=10, so x=1x=-1 is correct. The question tests if student can verify by substitution. Many students might make sign errors when moving 3x-3x or adding constants, but here the solution is valid.

Q5. The graph of y=5x2y = 5x - 2 and y=3x+8y = 3x + 8 intersect at point PP. What are the coordinates of PP?

A.(5,23)(5, 23)
B.(3,13)(3, 13)
C.(5,23)(5, 23)
D.(5,27)( -5, -27)
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: Setting 5x2=3x+85x - 2 = 3x + 8 gives 2x=10x=52x = 10 \Rightarrow x=5. Substituting into either equation gives y=5(5)2=23y=5(5)-2=23. So point is (5,23)(5,23). This tests the connection between equation solving and intersection of linear graphs, a key conceptual bridge.

Q6. A mobile phone plan charges a fixed fee of \20 plus \0.10 per text. Another plan charges \12 plus \0.15 per text. For how many texts are the costs equal? Solve 20+0.10t=12+0.15t20 + 0.10t = 12 + 0.15t.

A.t=160t = 160
B.t=80t = 80
C.t=200t = 200
D.t=40t = 40
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: Subtract 0.10t0.10t from both sides: 20=12+0.05t20 = 12 + 0.05t. Subtract 12: 8=0.05t8 = 0.05t. Divide by 0.05: t=160t = 160. This models a real-world break-even scenario. A common mistake is to subtract 20 first, leading to 0.10t=8+0.15t0.10t = -8 + 0.15t then 0.05t=8t=160-0.05t = -8 \Rightarrow t=160 still correct, but sign errors are frequent.

Q7. Compare the two methods for solving 2x+9=6x72x + 9 = 6x - 7: Method A: Subtract 2x2x then add 7. Method B: Add 7 then subtract 6x6x. Which statement is true?

A.Both methods yield x=4x=4
B.Method A gives x=4x=4, Method B gives x=4x=-4
C.Method A gives x=4x=-4, Method B gives x=4x=4
D.Both methods yield x=4x=-4
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: Method A: 9=4x716=4xx=49 = 4x - 7 \Rightarrow 16=4x \Rightarrow x=4. Method B: 2x+16=6x16=4xx=42x+16 = 6x \Rightarrow 16=4x \Rightarrow x=4. Both are valid; order of inverse operations doesn't change the solution. This tests understanding that equation solving is flexible as long as operations are legal.

Q8. What is the value of xx in the equation 2x+53=x12\frac{2x+5}{3} = \frac{x-1}{2}?

A.x=13x = -13
B.x=7x = 7
C.x=7x = -7
D.x=13x = 13
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: Cross-multiply: 2(2x+5)=3(x1)4x+10=3x3x=132(2x+5) = 3(x-1) \Rightarrow 4x+10 = 3x-3 \Rightarrow x = -13. This involves fractions and constants on both sides, requiring distribution and careful integer arithmetic. A common error is to forget to distribute the 3 or 2 correctly.

Q9. A student writes the equation 8x3=5x+98x - 3 = 5x + 9 and solves it as follows: 8x5x=9+33x=12x=48x - 5x = 9 + 3 \Rightarrow 3x = 12 \Rightarrow x = 4. Is this correct? If not, identify the misconception.

A.Correct ✅
B.Incorrect; should be x=6x=6
C.Incorrect; sign error when moving constants
D.Incorrect; should divide by 3 first
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: The student moved all variable terms to left (subtract 5x5x) and constants to right (add 3). That yields 3x=123x = 12 which is correct. Then dividing by 3 gives 4. This is a perfectly valid method. The distractor 'sign error' is common when students incorrectly add/subtract, but here it's done correctly.

Q10. The equation 4(x2)=3(x+5)2x4(x-2) = 3(x+5) - 2x simplifies to which of the following before isolating xx?

A.4x8=3x+152x4x - 8 = 3x + 15 - 2x
B.4x8=3x+52x4x - 8 = 3x + 5 - 2x
C.4x2=3x+152x4x - 2 = 3x + 15 - 2x
D.4x8=3x+15+2x4x - 8 = 3x + 15 + 2x
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: Distribute correctly: 4(x2)=4x84(x-2) = 4x - 8. Right side: 3(x+5)=3x+153(x+5) = 3x+15, then subtract 2x2x gives 3x+152x=x+153x+15-2x = x+15. So equation becomes 4x8=x+154x - 8 = x+15. Option A shows the intermediate distribution step before combining like terms, which is correct. This tests the order of operations in multi-step equations.

Q11. A car rental company A charges \30 per day plus \0.20 per mile. Company B charges \$50 per day with no mileage fee. For a one-day rental, how many miles must you drive for the costs to be equal?

A.m=100m = 100
B.m=250m = 250
C.m=400m = 400
D.m=150m = 150
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: Set 30+0.20m=5030 + 0.20m = 50. Subtract 30: 0.20m=200.20m = 20. Divide by 0.20: m=100m=100. This is a simpler case where constant on one side is zero after moving. Students might incorrectly set 30=500.20m30 = 50 - 0.20m and get negative sign errors, but the solution is straightforward.

Q12. The solution to 3x+4=2x53x + 4 = 2x - 5 is x=9x = -9. Which of the following equations has a solution that is the reciprocal of this?

A.6x+8=4x106x + 8 = 4x - 10
B.3x+4=2x5\frac{3}{x} + 4 = \frac{2}{x} - 5
C.3x+4=(2x5)3x + 4 = -(2x - 5)
D.3x4=2x+5-3x - 4 = -2x + 5
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: Reciprocal of 9-9 is 1/9-1/9. Solving 3x+4=2x5\frac{3}{x} + 4 = \frac{2}{x} - 5: multiply by xx: 3+4x=25x9x=1x=1/93+4x = 2 - 5x \Rightarrow 9x = -1 \Rightarrow x = -1/9. This combines reciprocal concept with equation solving, testing deeper understanding of variable in denominator and inverse relationships.

Q13. A student solves 5x8=3x+125x - 8 = 3x + 12 and gets x=10x = 10. Another student solves 5x8=3x+125x - 8 = 3x + 12 by first adding 8 to both sides, then subtracting 3x3x, and gets x=10x = 10 as well. Which property justifies that both methods are valid?

A.Commutative property of addition ✅
B.Associative property of addition
C.Addition and subtraction properties of equality
D.Distributive property
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: Both methods use the addition property of equality (adding or subtracting the same quantity from both sides). The order doesn't matter because these properties allow us to perform any sequence of legal operations. This distinguishes between properties of numbers (commutative/associative) and properties of equations (equality properties).

Q14. Given the equation 2(3x1)=42(x+3)2(3x - 1) = 4 - 2(x + 3), a student expands to get 6x2=42x66x - 2 = 4 - 2x - 6. They then simplify to 6x2=2x26x - 2 = -2x - 2. What is the next correct step to solve for xx?

A.Add 2x2x to both sides, then add 2 ✅
B.Add 2 to both sides, then subtract 6x6x
C.Subtract 6x6x from both sides, then add 2
D.Add 2x2x to both sides, then subtract 2
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: After simplification, we have 6x2=2x26x - 2 = -2x - 2. To isolate xx, add 2x2x to both sides to get 8x2=28x - 2 = -2, then add 2 to get 8x=0x=08x = 0 \Rightarrow x=0. Option A is correct order. Option D would give 8x4=28x - 4 = -2 which is unnecessary. This tests the strategic sequence of inverse operations.

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