📝 How to verify a solution to an equation (14 MCQs)
📖 From Digital SAT Algebra • 2. Linear Equations And Inequalities • 14 questions available
What is How to verify a solution to an equation?
Definition:
Verifying a solution to an equation means substituting the proposed value of the variable back into the original equation to check if it makes the equation a true statement. If the left-hand side equals the right-hand side after substitution, the value is a correct solution; otherwise, it is not.
Working:
To verify, replace the variable with the number and simplify both sides independently using arithmetic operations. If the simplified values are equal, the solution is confirmed. For example, to verify for , substitute : , which matches the right-hand side.
Example:
Verify if is a solution to . Substitute: . Both sides equal , so is verified as a solution.
Reason:
Verification is essential to catch arithmetic errors and ensure the answer actually satisfies the original equation. It provides a reliable check that boosts confidence in the solution process.
📝 All How to verify a solution to an equation MCQs
Q1. A student claims that is a solution to . Without fully simplifying, which single substitution check would most efficiently disprove the claim?
📖 Explanation: Efficient verification requires comparing the simplified numerical values of both sides after substitution. Option C is the only one that checks the entire equation. Substituting into only parts (A, B, D) is incomplete and cannot disprove the equality because errors in other terms might cancel or be missed, leading to a false conclusion.
Q2. Given the equation . If you simplify the right side to , which of the following is the best next step to verify if is a solution?
📖 Explanation: Since the simplified equation is mathematically equivalent to the original, substituting into either the original (B) or the simplified form (C) is valid. Option A is also correct but redundant. Option D correctly identifies that both B and C are acceptable verification methods, demonstrating understanding that simplification preserves equality.
Q3. Maria solved an equation and got . To verify, she substituted into the left side and got 12, and into the right side and got 12. She concluded the solution is correct. Is her conclusion always valid, and why?
📖 Explanation: While equal values confirm the equality at , verification must also ensure that the solution does not make any denominator zero or violate the domain of the original equation. Maria’s check is necessary but not sufficient for equations with variables in denominators. Option D highlights this critical, often-overlooked step in verification, which is a higher-order error analysis.
Q4. The graph of and intersect at the point . Which of the following statements is true about the equation ?
📖 Explanation: The intersection point means that when , both expressions yield . Therefore, satisfies the equation . Option A correctly interprets the graph. Options B and C confuse the x and y coordinates of the intersection point, a common misconception. Option D is false because intersection implies a solution exists.
Q5. A teacher writes on the board. Four students verify as follows. Who used the most rigorous verification method?
📖 Explanation: Bob’s method is the most rigorous because he explicitly computes both sides numerically and compares them. Carol’s statement is vague without computation. Alice relies on her solving process, which may have errors. David’s graph is a visual approximation, not an exact algebraic verification unless exact coordinates are given. Bob provides concrete, verifiable numerical evidence, making his method the strongest.
Q6. Consider the equation . A student verifies by substituting: . They conclude the solution is correct. Which critical step did they omit?
📖 Explanation: While the substitution works, the student must verify that the denominator is not zero at . Here, , so it's safe. However, the omission of this check is a critical error in verification, especially for rational equations. Option C correctly identifies this missing step, emphasizing that domain restrictions are part of solution verification, not just numerical equality.
Q7. Two equations are given: (I) and (II) . If is verified as a solution for (I), what can you conclude about (II) without solving it?
📖 Explanation: Equation (II) is exactly 2 times Equation (I). Since multiplying an equation by a non-zero constant produces an equivalent equation, any solution of (I) is also a solution of (II). Option A demonstrates this equivalence property. Options B, C, and D reflect misconceptions about equivalent equations, failing to recognize the scalar multiple relationship, which is a key algebraic concept.
Q8. A student claims that is a solution to . Their verification: , which is not 3. They conclude is not a solution. Is their reasoning and conclusion correct?
📖 Explanation: The student correctly substituted into the absolute value expression and obtained 1, which does not equal 3. Therefore, is indeed not a solution. Option A is correct. Options B and C are distractors: while has solutions and , that doesn't make a solution. Option D is false because the evaluation is correct. This tests whether students understand that verification is a definitive test.
Q9. Which of the following is NOT a valid way to verify if is a solution to ?
📖 Explanation: Options A, B, and C are all valid verification methods because they maintain the equality or compare equivalent forms. Option D is invalid because it ignores the constant term +4 on the left side, changing the equation. Substituting into only parts of an expression is a common error. This question requires students to analyze the validity of different verification procedures and identify an incomplete or incorrect method, testing error analysis skills.
Q10. The equation has a solution . If you multiply both sides by 0, you get . Is still a solution to the new equation ?
📖 Explanation: Multiplying an equation by 0 yields the identity , which is true for all , including . However, this operation is not reversible (it loses information), so the new equation is not equivalent to the original. While satisfies , it cannot be verified as a solution to the original equation using this transformed equation. Option D correctly distinguishes between 'satisfying the new equation' and 'being a solution to the original', a subtle and advanced concept.
Q11. A student simplifies to , then to , and finally . They verify by substituting into the original: LHS=6, RHS=6. Their verification is valid, but what is the deeper purpose of this step?
📖 Explanation: Verification serves two purposes: (1) it checks for arithmetic errors made during solving (Option A), and (2) it ensures the final value satisfies the original equation, especially when operations like multiplying by a variable or squaring might introduce extraneous solutions (Option C). Option D correctly combines both, showing a comprehensive understanding of why verification is essential, beyond just a routine check.
Q12. Given the system and , a student finds the intersection at (1,3). To verify the solution for the equation , they substitute into both linear expressions. Which of the following correctly interprets the verification?
📖 Explanation: The equation represents the x-coordinate of the intersection of the two lines. Substituting gives , verifying the equality (Option A). Graphically, this means the point (1,3) lies on both lines, confirming the intersection (Option B). Option C correctly combines both interpretations. This question requires students to connect algebraic verification with graphical meaning, testing mixed concepts and graph interpretation.
Q13. A student verifies for by computing LHS = and RHS = 4. They then state, 'Since LHS = RHS, the solution is verified.' Another student says, 'But you assumed the solution to check it, that's circular reasoning.' Who is correct?
📖 Explanation: Verification is not a proof of the solution's uniqueness or derivation; it's a confirmation that the proposed value satisfies the equation. The first student is correct that the check works. The second student raises a valid philosophical point: verification doesn't prove the solving steps were correct, but it does provide evidence. Option C captures this nuance: verification is a necessary (but not sufficient) check for correctness, not a circular argument. This tests deep understanding of the role of verification in mathematics.
Q14. A student solved and got solutions and . They verified : , works. For : , which is false, so they reject . Their verification process is correct, but what is the fundamental reason failed?
📖 Explanation: Squaring both sides of an equation can introduce extraneous solutions that satisfy the squared equation but not the original. Here, satisfies but not the original because the principal square root is non-negative, so . Option B is the algebraic reason, and Option C is the domain/logical reason. Option D correctly combines both, requiring students to understand the underlying cause of the failed verification, not just the procedural check.