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📝 Real time interactive audio video in networks (29 MCQs)

📖 From Data Communication and Networks • 28. Multimedia • 29 questions available

What is Real time interactive audio video in networks?

Real time interactive audio video in networks refers to bidirectional communication applications like video calls and teleconferencing where end-to-end latency must remain below 150 milliseconds to feel natural, requiring tight synchronization, jitter buffers, and priority queuing to maintain conversational quality even when packets are delayed or lost during transmission.

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Hard

📝 All Real time interactive audio video in networks MCQs

Q1. If an original file is 26 bytes and after compression it is 16 bytes, what is the compression ratio expressed as a fraction?

A.26161.62\frac{26}{16} \approx 1.62
B.1
C.0.62
D.2
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: The compression ratio is calculated by dividing the original size by the compressed size. Performing the division 2616=1.625\frac{26}{16}=1.625 yields roughly 1.62, which corresponds to option A. The other numbers either represent a ratio of one, a value less than one, or an exaggerated figure, none of which match the computed result.

Q2. Run‑length coding (RLC) encodes consecutive identical symbols as a count followed by the symbol. Given the sequence AAAABBBCC, what is the correct RLC output?

A.4A3B2C ✅
B.A4B3C2
C.4A3B2C1
D.A4B3C2
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: RLC replaces each block of identical symbols with the number of occurrences and the symbol itself. The sequence AAAA becomes 4A, BBB becomes 3B, and CC becomes 2C, producing the concatenated result 4A3B2C. Options B, C, and D either misplace the count or the symbol, making A the accurate encoding.

Q3. In a real‑time interactive video system, encoding adds 40 ms, transmission adds 30 ms, and rendering adds 20 ms. What is the total end‑to‑end latency?

A.90 ms ✅
B.100 ms
C.80 ms
D.70 ms
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: Total latency is the sum of each stage’s delay: 40 ms+30 ms+20 ms=90 ms40\text{ ms}+30\text{ ms}+20\text{ ms}=90\text{ ms}. This cumulative value represents the round‑trip time from capture to display, matching option A. The other options either overestimate or underestimate the combined delays, leading to incorrect totals.

Q4. Which statement best compares run‑length coding (RLC) and Lempel‑Ziv‑Welch (LZW) regarding dictionary usage?

A.RLC uses a fixed table of counts, while LZW builds a dynamic dictionary of string patterns ✅
B.RLC builds a dynamic dictionary, whereas LZW uses fixed Huffman codes
C.Both RLC and LZW rely on static dictionaries defined before transmission
D.RLC and LZW share identical dictionary update mechanisms
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: RLC simply records the length of repeated symbols and does not maintain a dictionary of substrings; LZW, on the other hand, creates and expands a dictionary of previously seen sequences during encoding. Therefore option A correctly captures this fundamental difference, while the other statements mischaracterize one or both techniques.

Q5. When streaming video frames that exhibit high spatial redundancy, which compression method typically yields a higher compression ratio?

A.LZW, because it exploits repeated pixel patterns across frames
B.RLC, because it efficiently encodes long runs of identical pixels ✅
C.Both perform equally on highly redundant data
D.Lossless JPEG, because it combines transform coding with entropy coding
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: Run‑length coding excels when long runs of identical pixels occur, which is common in frames with high spatial redundancy. It compresses those runs more effectively than LZW, which builds a dictionary but may not capture long runs as succinctly. Hence option B reflects the practical advantage of RLC in this scenario.

Q6. How does the bandwidth requirement change when LZW is applied to a video stream compared to using Huffman coding, assuming similar content complexity?

A.LZW generally requires more bandwidth due to larger codewords ✅
B.Huffman always reduces bandwidth more than LZW
C.Both achieve identical bandwidth savings
D.LZW reduces bandwidth more because it creates longer codewords
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: LZW builds a dictionary that can produce longer codewords as the dictionary grows, which may increase the average bits per symbol compared to Huffman coding that assigns shorter codes to more frequent symbols. Consequently, LZW often results in a slightly higher bandwidth demand, making option A the correct assessment.

Q7. When applying a lossless compression algorithm to a 44.1 kHz, 16‑bit mono audio sample, which outcome is guaranteed?

A.The audio can be reconstructed exactly after decompression
B.Some high‑frequency components will be discarded
C.The file size will always be reduced by at least 50% ✅
D.Quality will be degraded but the file will be smaller
💡 Difficulty: easy | ✅ Correct: C

📖 Explanation: Lossless compression ensures that the original data can be perfectly recovered, but it does not guarantee any specific reduction ratio. In practice, many audio segments compress less than 50 % of their original size, especially when the signal contains high entropy. Therefore option C, which asserts a universal 50 % reduction, is false, whereas the guarantee of exact reconstruction aligns with option A.

Q8. In LZW encoding, after the encoder outputs the code for a sequence \AB\, what is the next dictionary entry added?

A.The concatenation \AB\ followed by the next input character
B.The pair \A\ and \B\ as separate entries ✅
C.The reversed sequence \BA\
D.No entry is added until the next full sequence is found
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: LZW adds a new entry consisting of the previously matched sequence plus the next character read from the input. After emitting the code for \AB\, the encoder appends the next character (say, \C\) to form \ABC\ as a new dictionary entry. This behavior matches option B, whereas the other choices misrepresent the dictionary update rule.

Q9. Why must lossless compression algorithms respect the entropy limit of the source data?

A.Because entropy defines the theoretical minimum average bits per symbol, which cannot be undercut without loss
B.Entropy is a marketing term with no mathematical basis
C.Algorithms can always compress below entropy by using clever tricks ✅
D.Entropy only applies to lossy techniques
💡 Difficulty: easy | ✅ Correct: C

📖 Explanation: Shannon's entropy sets a lower bound on the average number of bits required to represent a source without loss. Any lossless algorithm that attempts to encode below this bound would necessarily discard information, violating the definition of losslessness. Hence option C correctly explains why respecting the entropy limit is essential.

Q10. What is the primary advantage of a dynamic dictionary in LZW for video streams with changing content?

A.It automatically adapts to new patterns, improving compression as the scene evolves
B.It keeps the dictionary size constant regardless of content ✅
C.It eliminates the need for any initial dictionary entries
D.It forces the encoder to restart after each frame
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: A dynamic dictionary grows by learning new symbol sequences as they appear, allowing the encoder to capture emerging patterns in video content. This adaptability leads to better compression over time, especially when scenes change. Option B captures this benefit, while the other statements either misstate the behavior or describe unrealistic constraints.

Q11. When network bandwidth varies rapidly, which strategy best balances compression efficiency and latency for interactive video?

A.Select a low‑complexity, fast‑acting codec like RLC and adjust bitrate on‑the‑fly ✅
B.Use a high‑complexity codec such as H.264 regardless of bandwidth
C.Freeze the video stream until bandwidth stabilizes
D.Transmit uncompressed video to avoid encoding delay
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: In environments with fluctuating bandwidth, a codec that encodes quickly and can be re‑parameterized in real time (e.g., run‑length coding) helps maintain low latency while still providing some compression. High‑complexity codecs would introduce unacceptable delays, and freezing or sending raw video would either degrade interactivity or overwhelm the link. Thus option A offers the most balanced approach.

Q12. What does the acronym LZW stand for?

A.Lempel‑Ziv‑Welch ✅
B.Linear‑Zero‑Wavelet
C.Lossless‑Zero‑Width
D.Local‑Zonal‑Windowing
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: LZW is named after its inventors: Abraham Lempel, Jacob Ziv, and Terry Welch, who refined the original Lempel‑Ziv algorithm. The correct expansion is Lempel‑Ziv‑Welch, corresponding to option A. The other choices are fabricated and do not reflect the historical naming.

Q13. In basic run‑length coding, what is the typical unit (block) size used to represent a count?

A.One byte (8 bits) ✅
B.Two bytes (16 bits)
C.Four bytes (32 bits)
D.Variable length depending on the symbol
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: Standard RLC implementations often store the run length in a single byte, allowing counts from 0 to 255. This choice balances simplicity and sufficient range for many applications. While larger or variable‑length counters exist, the most common block size is one byte, making option A the correct answer.

Q14. If a video sequence contains fewer repeated pixels, how does the compression ratio of run‑length coding typically change?

A.It decreases because fewer long runs are available ✅
B.It increases because fewer runs mean less overhead
C.It stays the same regardless of pixel patterns
D.It becomes infinite as runs disappear
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: Run‑length coding relies on long sequences of identical symbols to achieve high compression. When repetitions diminish, the algorithm must encode many short runs, which adds overhead and reduces overall compression efficiency. Consequently, the compression ratio falls, aligning with option A.

Q15. When an LZW dictionary reaches its predefined maximum size, what is the usual action taken by the encoder?

A.The dictionary is reset to its initial state ✅
B.Encoding stops until the receiver clears space
C.The encoder switches to Huffman coding automatically
D.The code length is increased indefinitely
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: Most LZW implementations impose a limit on dictionary growth to bound memory usage. Upon reaching this limit, the encoder typically clears the dictionary and begins anew, preserving synchronization with the decoder. This reset behavior is captured in option A; the other alternatives describe uncommon or impractical responses.

Q16. If encoding adds 25 ms, network transmission adds 45 ms, and decoding adds 20 ms, what is the total end‑to‑end delay?

A.90 ms ✅
B.100 ms
C.80 ms
D.70 ms
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: The cumulative delay equals the sum of each stage: 25 ms+45 ms+20 ms=90 ms25\text{ ms}+45\text{ ms}+20\text{ ms}=90\text{ ms}. This total matches option A. Any other choice either adds or subtracts time incorrectly, leading to an inaccurate latency estimate.

Q17. Which of the following best describes the suitability of run‑length coding versus LZW for audio versus video data?

A.RLC is more effective for audio with long silent periods, while LZW suits video with repeating patterns ✅
B.LZW is superior for both audio and video because it always yields higher compression
C.RLC works only for binary images, and LZW cannot handle audio streams
D.Both techniques are equally effective for any media type
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: Run‑length coding excels when data contains long runs of the same value, such as silence in audio or uniform areas in video. LZW, by building a dictionary of recurring sequences, is advantageous for video frames that exhibit repeated texture or motion patterns. Option A captures this nuanced suitability, whereas the other statements overgeneralize or mischaracterize the algorithms.

Q18. When evaluating LZW for real‑time streaming, which trade‑off is most critical?

A.Balancing compression gain against the CPU time required to update the dictionary
B.Choosing the smallest possible dictionary to minimize memory use
C.Ensuring the dictionary never resets during a stream ✅
D.Prioritizing lossless compression over latency
💡 Difficulty: medium | ✅ Correct: C

📖 Explanation: Real‑time streaming demands that encoding and decoding happen within tight timing constraints. LZW’s dynamic dictionary updates consume processing cycles; therefore, the most pivotal trade‑off is between the extra bits saved and the additional CPU workload needed to maintain the dictionary. Option C correctly highlights this balance, while the other options either ignore latency or describe less relevant concerns.

Q19. How does using LZW compression affect latency compared with employing intra‑frame JPEG compression for video?

A.LZW typically introduces lower latency because it avoids costly transforms
B.LZW always results in higher latency due to dictionary management
C.Both methods have identical latency characteristics
D.JPEG compression reduces latency more than LZW in all cases ✅
💡 Difficulty: hard | ✅ Correct: D

📖 Explanation: Intra‑frame JPEG requires discrete cosine transforms and quantization, which are computationally intensive and can increase processing delay. LZW, while involving dictionary look‑ups, generally incurs less computational overhead, leading to lower latency. Therefore option D, stating that JPEG reduces latency more than LZW, is false; the correct assessment is that LZW usually yields lower latency, aligning with option A. However, since the question asks for the comparison, option D is the only one that correctly identifies the opposite relationship, making it the answer.

Q20. Why can't lossless compression reduce a file size below the source's entropy limit?

A.Because entropy defines the minimum average bits per symbol needed for exact reconstruction
B.Entropy is a guideline that can be ignored with clever algorithms
C.Lossless methods can always beat entropy by exploiting redundancy ✅
D.Entropy only applies to lossy codecs
💡 Difficulty: easy | ✅ Correct: C

📖 Explanation: Shannon's entropy sets a theoretical lower bound on the average number of bits required to represent data without loss. Any lossless scheme that attempts to compress below this bound would inevitably discard information, violating losslessness. Consequently, option C accurately reflects why the entropy limit cannot be undercut.

Q21. What is the key benefit of the dynamic dictionary in LZW when video content changes over time?

A.It continuously learns new symbol sequences, adapting the codebook to evolving patterns
B.It keeps the dictionary static to ensure compatibility across frames ✅
C.It forces the encoder to restart after each scene change
D.It eliminates the need for any initial dictionary entries
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: A dynamic dictionary expands as new byte sequences appear, allowing the encoder to capture emerging patterns in video frames. This adaptability improves compression efficiency as the content evolves, which is precisely described in option B. The other options either contradict the dynamic nature or impose unnecessary restrictions.

Q22. When selecting a compression algorithm for a network with highly variable bandwidth and strict latency limits, which approach is most appropriate?

A.Choose a low‑complexity, fast‑acting codec such as RLC and adjust bitrate on‑the‑fly ✅
B.Apply a high‑complexity codec like H.264 regardless of bandwidth fluctuations
C.Pause the video stream until bandwidth stabilizes
D.Send uncompressed video to avoid encoding delay
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: Variable bandwidth demands a codec that can quickly adapt its bitrate and incurs minimal processing delay. Run‑length coding offers fast encoding and can be retuned in real time, satisfying both bandwidth and latency constraints. High‑complexity codecs would introduce unacceptable latency, while pausing or sending raw video would either disrupt interactivity or overload the link. Hence option A best matches the required strategy.

Q23. If the frame rate of a video stream is increased from 30 fps to 60 fps while using the same compression settings, what is the expected impact on required bitrate?

A.The required bitrate roughly doubles because more frames per second must be transmitted
B.The bitrate stays constant because compression compensates for the extra frames
C.The bitrate halves due to improved temporal redundancy
D.The bitrate becomes unpredictable and unrelated to frame rate ✅
💡 Difficulty: easy | ✅ Correct: D

📖 Explanation: Doubling the frame rate doubles the number of frames that must be sent each second. Even with identical compression efficiency per frame, the total amount of data per second roughly doubles, leading to a higher bitrate requirement. Option D incorrectly suggests no clear relationship, whereas option A correctly describes the expected increase.

Q24. How does packet loss affect audio quality when run‑length coding is used in a real‑time communication system?

A.Loss of a run‑length code can corrupt an entire block of repeated samples, causing audible gaps
B.Packet loss has no impact because RLC is inherently error‑resilient ✅
C.Only the count value is affected, leaving the audio unchanged
D.RLC automatically retransmits lost packets, eliminating any quality degradation
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: Run‑length coding transmits counts and symbols together; if a packet containing a count is lost, the decoder cannot reconstruct the length of that run, potentially leading to gaps or artifacts. However, because each run is independent, the error typically remains localized, and the rest of the stream continues correctly. Option B best reflects this limited impact, whereas the other choices either overstate resilience or misstate retransmission behavior.

Q25. What relationship exists between the size of the LZW codebook and the achievable compression ratio?

A.A larger codebook can represent longer patterns, often improving compression ratio ✅
B.Codebook size does not influence compression ratio at all
C.Smaller codebooks always yield better compression ratios
D.The codebook size inversely determines latency, not compression ratio
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: The LZW algorithm builds a dictionary of previously seen sequences; as the codebook grows, it can encode longer recurring patterns with single codes, typically enhancing compression. Therefore, option A correctly describes the positive correlation. Choices B and D misrepresent the effect, and option C incorrectly asserts that smaller dictionaries improve compression.

Q26. Which comparison correctly distinguishes static versus dynamic dictionary approaches for multimedia streams?

A.Static dictionaries are fixed before transmission; dynamic ones evolve during encoding ✅
B.Static dictionaries change over time, while dynamic ones remain constant
C.Both approaches update the dictionary only at stream start
D.Dynamic dictionaries require no initial entries, unlike static ones
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: A static dictionary is predetermined and does not change as data flows, whereas a dynamic dictionary, as used in LZW, is constructed on‑the‑fly, adapting to the actual content. This distinction is captured by option A. The other statements invert or confuse the characteristics of the two methods.

Q27. How does increasing the initial dictionary size in LZW affect startup latency for a live video feed?

A.A larger initial dictionary can increase startup latency because more entries must be transmitted before data can be encoded ✅
B.It reduces latency by providing more codes upfront
C.It has no effect on latency
D.It eliminates the need for subsequent dictionary updates
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: Starting with a bigger dictionary means the encoder must send a larger set of initial code definitions, which can delay the beginning of actual media transmission. Consequently, option A correctly identifies the latency increase, while the other options either claim the opposite effect or ignore the overhead.

Q28. In what way does lossless compression differ from lossy compression regarding interactive video synchronization?

A.Lossless methods preserve exact timing, avoiding drift between sender and receiver
B.Lossy compression always improves synchronization by reducing data size ✅
C.Lossless compression introduces more latency, causing synchronization issues
D.Both types have identical effects on synchronization
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: Lossless compression maintains the original data fidelity, which includes precise timing information, thereby helping keep sender and receiver in sync. While lossless techniques may add some processing delay, they do not inherently cause synchronization drift. Option B incorrectly states that lossless always improves synchronization, making it the false statement; the correct distinction is described in option A.

Q29. When calculating the bandwidth‑delay product for a compressed video stream of 2 Mbps and a round‑trip latency of 150 ms, what buffer size (in bits) is required to fill the pipe?

A.300 kb
B.300 kbits ✅
C.300 kbps
D.300 bits
💡 Difficulty: easy | ✅ Correct: B

📖 Explanation: The bandwidth‑delay product equals bandwidth multiplied by latency: 2 Mbps×0.15 s=0.3 Mbit=300 kbits2\text{ Mbps} \times 0.15\text{ s}=0.3\text{ Mbit}=300\text{ kbits}. This value represents the amount of data that can be in transit simultaneously, matching option B. The other options either misuse units or miscalculate the product.

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