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📝 Initialization of 8259

📖 From An Introduction To Microprocessor 8085 • 11. Programmable Interrupt Controller: 8259 • 4 questions available

Practice MCQs for Initialization of 8259. Test your knowledge with carefully crafted questions across easy, medium, and hard difficulty levels.

🔄 Last updated: 2026-07-30

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📝 Sample Questions

Q1. A system wants to load counter 1 of the 8253. Which control‑signal combination must be asserted?

🔹 A. CS=0, RD=0, WR=1, A1=0, A0=0
🔹 B. CS=0, RD=1, WR=0, A1=0, A0=1
🔹 C. CS=0, RD=1, WR=0, A1=1, A0=0
🔹 D. CS=0, RD=0, WR=1, A1=1, A0=1

💡 Difficulty: easy | ✅ Correct: A

Q2. Why is the Chip Select (CS) input of the 8253 designed as an active‑low signal?

🔹 A. It reduces the number of required pins on the CPU.
🔹 B. It allows the device to stay enabled when the bus is idle.
🔹 C. It lets multiple peripherals share the same address space without conflict.
🔹 D. It simplifies the internal decoding logic of the chip.

💡 Difficulty: medium | ✅ Correct: D

Q3. Which control‑signal pattern causes the 8253 to perform no operation (3‑state) regardless of the address lines?

🔹 A. CS=0, RD=0, WR=0, A1=0, A0=0
🔹 B. CS=0, RD=1, WR=0, A1=1, A0=1
🔹 C. CS=0, RD=1, WR=1, A1=0, A0=0
🔹 D. CS=0, RD=0, WR=1, A1=1, A0=1

💡 Difficulty: hard | ✅ Correct: C

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🔗 Related Topics

📝 Programmable Interrupt Controller 8259📝 Block Diagram of 8259📝 Interfacing of 8259A with 8085A📝 Vectoring Data Formats for 8259📝 Initialization Command Words(ICWs) of 8259
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