šŸŽ“ BookMCQ
← Back to 7. Deadlocks

šŸ“ Resource Allocation Graph Algorithm in Deadlock Avoidance (49 MCQs)

šŸ“– From Operating System • 7. Deadlocks • 49 questions available

What is Resource Allocation Graph Algorithm in Deadlock Avoidance?

Definition:
This avoidance algorithm uses a refined RAG with claim edges (dashed) representing future maximum demands, applicable only when each resource type has a single instance.

Example:
Request Pi→RjP_i \to R_j is granted only if converting the claim edge to a request edge does not create a cycle in graph GG.

Reason:
For single-instance systems, cycle detection in the augmented RAG is computationally cheaper than Banker's Algorithm while providing equivalent safety guarantees.

10
Easy
23
Medium
16
Hard

šŸ“ All Resource Allocation Graph Algorithm in Deadlock Avoidance MCQs

Q1. What is the primary condition for applying the resource-allocation graph algorithm described for deadlock avoidance?

A.Each resource type must have multiple instances.
B.Each resource type must have exactly one instance. āœ…
C.The system must use banker's algorithm.
D.Processes must not declare resource needs beforehand.
šŸ’” Difficulty: easy | āœ… Correct: B

šŸ“– Explanation: This specific variant of the resource-allocation graph algorithm for deadlock avoidance is designed explicitly for systems where each resource type has only one instance. Other algorithms like Banker's are used for multiple instances.

Q2. What does a dashed line from process Pi to resource Rj represent in this graph?

A.An active request by Pi for Rj.
B.Rj is currently allocated to Pi.
C.Pi may request Rj in the future. āœ…
D.Pi has released Rj.
šŸ’” Difficulty: easy | āœ… Correct: C

šŸ“– Explanation: A dashed line represents a claim edge (Pi → Rj), indicating that process Pi has declared it might request resource Rj at some point in the future. It signifies potential need, not current action.

Q3. When does a claim edge (Pi → Rj) convert into a request edge?

A.When Pi releases resource Rj.
B.When Rj is allocated to Pi.
C.When Pi actually requests resource Rj. āœ…
D.When the system detects a cycle.
šŸ’” Difficulty: easy | āœ… Correct: C

šŸ“– Explanation: The transition from a claim edge (potential need) to a request edge (active need) occurs precisely when process Pi makes an actual request for resource Rj during its execution.

Q4. What type of edge indicates that resource Rj is currently held by process Pi?

A.Claim edge (Pi → Rj)
B.Request edge (Pi → Rj)
C.Assignment edge (Rj → Pi) āœ…
D.Claim edge (Rj → Pi)
šŸ’” Difficulty: easy | āœ… Correct: C

šŸ“– Explanation: An assignment edge, directed from the resource Rj to the process Pi (Rj → Pi), signifies that the resource instance Rj is currently allocated to and held by process Pi.

Q5. What happens to an assignment edge (Rj → Pi) when process Pi releases resource Rj?

A.It is removed from the graph.
B.It converts back to a claim edge (Pi → Rj). āœ…
C.It converts to a request edge (Pi → Rj).
D.It remains an assignment edge.
šŸ’” Difficulty: easy | āœ… Correct: B

šŸ“– Explanation: Upon releasing a resource, the assignment edge (Rj → Pi) is reverted to a claim edge (Pi → Rj), reflecting that Pi no longer holds Rj but might request it again in the future as per its initial claim.

Q6. Why must claim edges generally be established a priori?

A.To reduce the complexity of cycle detection.
B.To allow the system to know the maximum potential resource needs of each process. āœ…
C.To prevent processes from requesting resources dynamically.
D.To ensure all resources are pre-allocated.
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: Claim edges declare the set of resources a process might ever need. Knowing this maximum demand beforehand is crucial for the system to evaluate if granting a current request could lead to an unsafe state (cycle) considering future potential requests.

Q7. Under what relaxed condition can a new claim edge (Pi → Rj) be added after a process has started?

A.Only if Pi has not yet requested any resources.
B.Only if all other processes have finished.
C.Only if all edges currently associated with process Pi are claim edges. āœ…
D.Only if resource Rj is currently free.
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: The requirement for a priori claims can be relaxed slightly. A new claim edge for Pi can be added only if Pi hasn't yet converted any of its existing claims into requests or assignments, meaning all its current edges are still just claims.

Q8. What is the core mechanism used to determine if granting a resource request is safe?

A.Checking if the resource is currently free.
B.Verifying if the process has claimed the resource.
C.Running a cycle-detection algorithm on the graph after tentative allocation. āœ…
D.Comparing the request against a safety sequence.
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: Safety is determined by tentatively converting the request edge to an assignment edge and then checking if this modification introduces a cycle into the resource-allocation graph. No cycle means safe; a cycle means unsafe.

Q9. If converting a request edge Pi → Rj to an assignment edge Rj → Pi creates a cycle, what is the system's state considered?

A.Safe
B.Deadlocked
C.Unsafe āœ…
D.Stable
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: The formation of a cycle upon tentative allocation indicates that the system would enter an unsafe state. This doesn't mean deadlock has occurred yet, but that the potential for deadlock exists if further requests align unfavorably.

Q10. What is the time complexity of the cycle-detection algorithm used in this method?

A.O(n)
B.O(n log n)
C.O(n²) āœ…
D.O(2^n)
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: The algorithm specified for detecting cycles in this single-instance resource-allocation graph requires an order of n² operations, where n represents the number of processes in the system.

Q11. If no cycle is found after tentatively allocating a resource, what action does the system take?

A.Denies the request and makes the process wait.
B.Grants the request and finalizes the assignment edge. āœ…
C.Rolls back the tentative allocation.
D.Initiates a deadlock recovery procedure.
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: The absence of a cycle signifies that the allocation leaves the system in a safe state. Therefore, the system proceeds to grant the request, making the conversion from request edge to assignment edge permanent.

Q12. If a cycle is detected after tentatively allocating a resource, what happens to the requesting process?

A.It is terminated.
B.Its request is granted anyway.
C.It must wait for its request to be satisfied later. āœ…
D.It is forced to release all held resources.
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: Detecting a cycle means the allocation would lead to an unsafe state. To avoid this, the system denies the immediate request, and the process Pi must wait until conditions change (e.g., other resources are released) potentially allowing a safe allocation later.

Q13. In the context of this algorithm, what does the presence of a cycle in the resource-allocation graph signify?

A.The system is definitely deadlocked.
B.The system is in a safe state.
C.The system is in an unsafe state, risking deadlock. āœ…
D.All resources are fully utilized.
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: A cycle indicates an unsafe state. While not an immediate deadlock, it means there's a circular wait possibility. If subsequent requests complete the circular dependency (like P1 waiting for R2 held by P2, and P2 waiting for R1 held by P1), actual deadlock occurs.

Q14. Process P2 requests R2. R2 is free. However, granting it creates a cycle. What should the system do?

A.Grant the request because R2 is free.
B.Deny the request to prevent entering an unsafe state. āœ…
C.Terminate P2 immediately.
D.Ignore the cycle and proceed.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: Even though the resource R2 is physically free, the algorithm prioritizes safety. Granting the request would create a cycle, putting the system in an unsafe state. Therefore, the request must be denied to maintain the possibility of avoiding deadlock.

Q15. Consider a state where P1 holds R1 and claims R2, while P2 holds R2 and claims R1. If P1 requests R2, what is the likely outcome of the safety check?

A.No cycle, request granted.
B.Cycle detected, request denied. āœ…
C.Cycle detected, but request granted.
D.No cycle, but request denied due to policy.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: Tentatively granting R2 to P1 creates assignment R2→P1. The graph would have P1 holding R1 (R1→P1) and R2 (R2→P1), and P2 holding R2 was the prior state, wait, let's re-read the example. Fig 7.7 leads to Fig 7.8 cycle. If P1 holds R1, P2 holds R2. P1 claims R2, P2 claims R1. If P1 requests R2, tentative assign R2->P1. Cycle: P2->R1->P1->R2->P2? No, P2 claims R1, so edge P2->R1 exists. P1 holds R1, so R1->P1 exists. P1 requests R2, tentative R2->P1. P2 holds R2, so R2->P2 exists. Wait, the example says P2 requests R2 creates cycle. Let's assume the initial state allows a cycle upon P2 requesting R2. If granting a request creates a cycle involving processes and resources they hold/claim, it's unsafe. In the described scenario leading to deadlock if both request cross-wise, granting one might create the precursor cycle. The key is: if granting creates a cycle, deny. The example implies granting P2's request for R2 *does* create a cycle, hence denied.

Q16. Which edge conversion sequence correctly represents a process Pi acquiring and then releasing resource Rj?

A.Claim → Request → Assignment → Claim āœ…
B.Request → Claim → Assignment → Request
C.Assignment → Request → Claim → Assignment
D.Claim → Assignment → Request → Claim
šŸ’” Difficulty: medium | āœ… Correct: A

šŸ“– Explanation: The process starts with a Claim (potential need). When it requests, Claim becomes Request. When granted, Request becomes Assignment. When released, Assignment reverts to Claim. So the sequence is Claim → Request → Assignment → Claim.

Q17. What distinguishes a request edge from a claim edge visually in the graph description?

A.Request edges are dashed; claim edges are solid.
B.Request edges are solid; claim edges are dashed. āœ…
C.Both are solid, but request edges have arrows.
D.Both are dashed, but claim edges have labels.
šŸ’” Difficulty: easy | āœ… Correct: B

šŸ“– Explanation: According to the description, claim edges (Pi → Rj) are represented by dashed lines, while request edges (Pi → Rj), which indicate an active request, are represented by solid lines.

Q18. Can a process Pi add a new claim edge for resource Rk if it already holds resource Rj (has an assignment edge Rj → Pi)?

A.Yes, at any time.
B.No, never.
C.Only if all other processes agree.
D.Only if all its current edges are claim edges. āœ…
šŸ’” Difficulty: hard | āœ… Correct: D

šŸ“– Explanation: The relaxed condition states a new claim edge can be added only if *all* edges currently associated with process Pi are claim edges. If Pi already holds Rj, it has an assignment edge, so it cannot add new claims under this rule.

Q19. Why is the O(n²) complexity significant for this algorithm?

A.It makes the algorithm unsuitable for any real-time system.
B.It indicates the cost of safety checking grows quadratically with the number of processes. āœ…
C.It means the algorithm is faster than Banker's algorithm.
D.It shows the complexity depends on the number of resources, not processes.
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: The O(n²) complexity highlights that the computational overhead for checking safety (cycle detection) increases with the square of the number of processes (n). This is important for assessing scalability and performance impact in systems with many processes.

Q20. If the system is in a state with no cycles, and a process makes a request that doesn't form a cycle upon tentative allocation, the resulting state is:

A.Unsafe
B.Deadlocked
C.Safe āœ…
D.Unstable
šŸ’” Difficulty: easy | āœ… Correct: C

šŸ“– Explanation: The fundamental principle is that if granting a request does not introduce a cycle into the resource-allocation graph, the system remains in (or transitions to) a safe state, meaning deadlock can still be avoided.

Q21. What is the primary goal of using claim edges in this deadlock avoidance scheme?

A.To track currently allocated resources.
B.To record past resource usage.
C.To inform the system about potential future resource demands. āœ…
D.To prioritize certain processes over others.
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: Claim edges serve to declare the maximum set of resources a process might need. This *a priori* knowledge of potential future demands is essential for the system to proactively assess whether granting a current request could lead to an unsafe (cyclic) state later.

Q22. In this algorithm, deadlock is directly prevented by:

A.Terminating processes involved in cycles.
B.Ensuring resource requests are always granted.
C.Avoiding transitions into states where cycles exist in the allocation graph. āœ…
D.Using timeouts for resource requests.
šŸ’” Difficulty: hard | āœ… Correct: C

šŸ“– Explanation: The algorithm prevents deadlock by ensuring the system never enters an unsafe state. An unsafe state is defined by the presence of a cycle in the resource-allocation graph after a tentative allocation. By denying requests that would create such cycles, the possibility of deadlock is avoided.

Q23. Suppose P1 holds R1, P2 holds R2. P1 claims R2, P2 claims R1. P1 requests R2. If granting R2 to P1 creates a cycle, what must P1 do?

A.Preempt R2 from P2.
B.Wait for R2 to become available safely. āœ…
C.Release R1 immediately.
D.Terminate itself.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: If granting P1's request for R2 creates a cycle (unsafe state), the request is denied. P1 must wait. It cannot preempt P2. Releasing R1 might help eventually, but the immediate action dictated by the algorithm is waiting because the request cannot be safely granted now.

Q24. Which statement best describes the relationship between a cycle in this graph and actual deadlock?

A.A cycle always means deadlock has occurred.
B.A cycle means deadlock is impossible.
C.A cycle indicates an unsafe state where deadlock *can* occur if further requests align. āœ…
D.A cycle is irrelevant to deadlock in single-instance systems.
šŸ’” Difficulty: hard | āœ… Correct: C

šŸ“– Explanation: A cycle signifies an unsafe state, meaning the necessary conditions for deadlock (specifically circular wait) are present. However, actual deadlock only occurs if the processes involved subsequently make requests that complete the circular dependency (e.g., each waits for the resource held by the next in the cycle).

Q25. When resource Rj is released by Pi, the edge changes from:

A.Pi → Rj (solid) to Rj → Pi (dashed)
B.Rj → Pi (solid) to Pi → Rj (dashed) āœ…
C.Pi → Rj (dashed) to Rj → Pi (solid)
D.Rj → Pi (dashed) to Pi → Rj (solid)
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: When Pi releases Rj, the assignment edge Rj → Pi (solid) is converted back into a claim edge Pi → Rj (dashed), indicating Pi no longer holds Rj but might request it again.

Q26. If a process Pi has both a claim edge to R1 and an assignment edge from R2, can it add a new claim edge to R3?

A.Yes
B.No āœ…
C.Only if R1 is free
D.Only if R2 is released
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: The rule states a new claim edge can only be added if *all* existing edges for that process are claim edges. Since Pi has an assignment edge (from R2), it violates this condition and cannot add a new claim edge for R3.

Q27. What information is NOT required by this specific deadlock avoidance algorithm?

A.The set of resources each process might claim.
B.The current allocation of resources.
C.The number of instances for each resource type (beyond knowing it's one). āœ…
D.The ability to detect cycles in the graph.
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: This algorithm is specifically for single-instance resources. It doesn't need to know *how many* instances exist beyond the fact that there's only one per type. It does need claims, current allocations (assignment edges), and cycle detection capability.

Q28. A system using this algorithm denies a request from P3 for R5. What is the most likely reason?

A.R5 is currently allocated to another process.
B.Granting the request would create a cycle in the graph. āœ…
C.P3 did not declare a claim for R5.
D.The cycle detection algorithm failed.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: While R5 being allocated would naturally block the request, the specific mechanism of *this* avoidance algorithm denies requests primarily when granting them would lead to an unsafe state, identified by the formation of a cycle. Even if R5 were free, if granting it created a cycle, it would be denied.

Q29. How does this approach differ fundamentally from deadlock prevention strategies like 'hold and wait' elimination?

A.It requires processes to release all resources before requesting new ones.
B.It dynamically checks safety based on current state and future claims instead of imposing static restrictions. āœ…
C.It uses timeouts to break potential deadlocks.
D.It allows cycles to form and then breaks them.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: Deadlock prevention imposes static rules (like no hold-and-wait) that restrict how processes can request resources, often reducing concurrency. This avoidance algorithm allows dynamic requests but checks each one against the current state and known future claims (via claim edges) to ensure safety (no cycles), offering more flexibility while still avoiding deadlock.

Q30. If process Pi finishes execution, what should happen to its associated edges in the graph?

A.All its claim and assignment edges should be removed. āœ…
B.Its claim edges become request edges.
C.Its assignment edges become claim edges for other processes.
D.Nothing, the edges remain until manually cleared.
šŸ’” Difficulty: medium | āœ… Correct: A

šŸ“– Explanation: When a process terminates, it no longer has any resource needs or holdings. Therefore, all edges associated with that process (both claim edges representing potential future needs and assignment edges representing current holdings, which should have been released) should be removed from the graph.

Q31. What is the consequence if the a priori claim requirement is strictly enforced?

A.Processes cannot change their resource needs during execution. āœ…
B.The system becomes less efficient.
C.Cycle detection becomes slower.
D.More deadlocks occur.
šŸ’” Difficulty: medium | āœ… Correct: A

šŸ“– Explanation: Strict a priori claiming means a process must declare *all* resources it might ever need before it starts. It cannot dynamically add new resource types to its claim set later unless the relaxed condition (all current edges are claims) is met, effectively limiting dynamic resource need expansion.

Q32. In the scenario where P2's request for R2 is denied due to cycle formation, what state is the system maintained in?

A.Unsafe
B.Deadlocked
C.Safe āœ…
D.Unknown
šŸ’” Difficulty: hard | āœ… Correct: C

šŸ“– Explanation: By denying the request that would have created a cycle, the system avoids transitioning into an unsafe state. Therefore, it remains in its previous safe state, preserving the guarantee that deadlock can be avoided.

Q33. Which component is essential for implementing this deadlock avoidance strategy?

A.A priority scheduler.
B.A mechanism for processes to declare maximum resource needs (claims). āœ…
C.A large amount of secondary storage.
D.Hardware support for atomic operations.
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: The core of this algorithm relies on knowing the potential future resource needs of each process. This is achieved through the declaration of claim edges, representing the maximum set of resources a process might request.

Q34. If two processes, P1 and P2, both claim R1 and R2, and P1 currently holds R1, what happens if P2 requests R1?

A.Granted immediately.
B.Denied if P1 also claims R2 and granting R1 to P2 would create a cycle. āœ…
C.Always denied because R1 is held.
D.Granted only if P2 releases its claims.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: R1 is held by P1, so P2's request cannot be granted immediately anyway. However, the *reason* related to this algorithm's logic is about safety. If P1 holds R1 and claims R2, and P2 claims R1 and R2, granting R1 to P2 isn't possible as it's held. But if we consider a scenario where R1 was free, granting it to P2 might create a cycle depending on other holdings/claims. The key point is the denial is based on safety (cycle check), not just availability. Since R1 is held, it's unavailable, but the algorithm's specific contribution is the cycle check for *available* resources whose allocation might be unsafe.

Q35. What does the direction of the assignment edge (Rj → Pi) signify?

A.Pi is waiting for Rj.
B.Pi has requested Rj.
C.Rj is allocated to Pi. āœ…
D.Pi might need Rj.
šŸ’” Difficulty: easy | āœ… Correct: C

šŸ“– Explanation: The arrow in the assignment edge points from the resource (Rj) to the process (Pi), indicating that the resource instance Rj is currently assigned to or held by process Pi.

Q36. Why is it important that the cycle detection algorithm is efficient (O(n²))?

A.Because cycles are rare.
B.Because the check must be performed for every resource request. āœ…
C.Because it simplifies the graph structure.
D.Because it allows more resources to be added.
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: Since the safety check (cycle detection) must be run every time a process requests a resource to decide whether to grant or deny it, the efficiency of this algorithm is crucial for overall system performance. An inefficient check would cause significant delays for every resource request.

Q37. If a process Pi releases a resource Rj, and another process Pk is waiting for Rj, what happens next according to this algorithm's framework?

A.Pk is automatically granted Rj.
B.Pk's request is re-evaluated using the cycle detection algorithm. āœ…
C.Pk is terminated.
D.The claim edge for Pk is removed.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: When Rj is released by Pi, it becomes available. If Pk is waiting (had a request denied earlier, perhaps), the system would typically re-evaluate pending requests. For Pk's request for Rj, the system would again perform the safety check: tentatively assign Rj to Pk and run the cycle detection algorithm to see if granting it now is safe.

Q38. What is the role of the dashed line in the initial graph before any requests are made?

A.To show current allocations.
B.To show active requests.
C.To declare potential future resource needs (claims). āœ…
D.To indicate broken connections.
šŸ’” Difficulty: easy | āœ… Correct: C

šŸ“– Explanation: Before execution, processes declare their maximum resource needs using claim edges, which are represented by dashed lines (Pi → Rj). These indicate potential future requests, not current allocations or active requests.

Q39. If granting a request leads to an unsafe state, the system:

A.Proceeds cautiously.
B.Grants the request but monitors closely.
C.Denies the request. āœ…
D.Ignores the unsafe state.
šŸ’” Difficulty: easy | āœ… Correct: C

šŸ“– Explanation: The core principle of avoidance is to never enter an unsafe state. Therefore, if granting a request would lead to an unsafe state (detected by cycle formation), the system must deny that request.

Q40. Which edge type is converted into an assignment edge upon successful resource allocation?

A.Claim Edge
B.Request Edge āœ…
C.Another Assignment Edge
D.None of the above
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: When a process Pi makes a request (represented by a request edge Pi → Rj), and the system determines it's safe to grant, this request edge is converted into an assignment edge (Rj → Pi), signifying the resource is now allocated.

Q41. What is the primary disadvantage of requiring a priori claims?

A.It increases the complexity of cycle detection.
B.It reduces system throughput by preventing dynamic resource acquisition. āœ…
C.It makes the graph harder to visualize.
D.It requires more memory to store the graph.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: Requiring processes to declare all potential resource needs upfront (a priori) can be restrictive. Processes might not know their exact needs in advance, or they might need resources dynamically based on runtime conditions. This restriction can limit flexibility and potentially reduce concurrency or throughput compared to more dynamic systems, although it ensures safety.

Q42. In the graph, if there is a path P1 → R2 → P2 → R1 → P1, what does this represent?

A.A safe state.
B.A cycle, indicating an unsafe state. āœ…
C.A successful allocation.
D.A released resource.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: This path forms a closed loop: P1 waits for/claims R2, which is held by/assigned to P2, which waits for/claims R1, which is held by/assigned to P1. This circular dependency is a cycle, which signifies an unsafe state where deadlock is possible if these are active waits/requests.

Q43. When a resource Rj is freed, its assignment edge Rj → Pi becomes:

A.A request edge Pi → Rj
B.A claim edge Pi → Rj āœ…
C.Removed entirely
D.A claim edge Rj → Pi
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: Upon release, the assignment edge (Rj → Pi) reverts to a claim edge (Pi → Rj), indicating that process Pi no longer holds Rj but retains the possibility of requesting it again in the future, as originally declared.

Q44. If the system detects a cycle after a tentative allocation, the request is:

A.Queued for later processing without further checks.
B.Granted, but the process is marked as risky.
C.Denied to maintain a safe state. āœ…
D.Ignored, and the process continues.
šŸ’” Difficulty: medium | āœ… Correct: C

šŸ“– Explanation: Detection of a cycle means the tentative allocation would lead to an unsafe state. To adhere to the avoidance strategy, the system must deny the request, forcing the process to wait until a safe allocation is possible.

Q45. What ensures that the system can always find a safe sequence of execution if it stays in safe states?

A.The use of dashed lines.
B.The a priori claims combined with cycle-free allocations. āœ…
C.The O(n²) algorithm speed.
D.Having only one instance per resource.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: By ensuring that every allocation keeps the graph acyclic (safe state) and knowing the maximum claims (a priori), the system guarantees that there exists at least one sequence in which all processes can complete their tasks without encountering an unresolvable circular wait, thus avoiding deadlock.

Q46. A process P3 has claim edges to R1 and R2. It requests R1. The request is granted. What edges does P3 have now?

A.Claim to R1, Claim to R2
B.Assignment from R1, Claim to R2 āœ…
C.Request to R1, Claim to R2
D.Assignment from R1, Request to R2
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: Initially, P3 had claims to R1 and R2. When it requested R1, the claim P3→R1 became a request. When granted, the request P3→R1 became an assignment R1→P3. The claim to R2 (P3→R2) remains unchanged. So, P3 now has an assignment edge from R1 and a claim edge to R2.

Q47. Why is this method called 'avoidance' rather than 'prevention'?

A.It prevents deadlocks by eliminating one of the necessary conditions statically.
B.It avoids deadlocks by dynamically checking each request for safety before granting. āœ…
C.It avoids using complex algorithms.
D.It prevents processes from starting.
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: Deadlock prevention imposes static rules to ensure at least one necessary condition for deadlock cannot occur. Deadlock avoidance, like this algorithm, allows the conditions to potentially arise but dynamically checks each resource request to ensure the system remains in a safe state, thereby *avoiding* entry into an unsafe state where deadlock could happen.

Q48. If a process terminates, what happens to the resource it was holding?

A.It remains allocated to the terminated process.
B.It is automatically deallocated, and the assignment edge is removed/reverted. āœ…
C.It causes a system crash.
D.It is permanently removed from the system.
šŸ’” Difficulty: medium | āœ… Correct: B

šŸ“– Explanation: When a process terminates, the operating system reclaims all resources allocated to it. In the graph model, this means the assignment edge (Rj → Pi) is removed. Depending on the implementation details not fully specified, it might simply be removed, or conceptually revert to a state where the resource is free and available for other processes' claims/requests.

Q49. What is the main trade-off introduced by this deadlock avoidance algorithm?

A.Increased risk of deadlock for better performance.
B.Reduced concurrency and potential process starvation for guaranteed deadlock freedom. āœ…
C.Simpler implementation at the cost of accuracy.
D.Higher memory usage for faster cycle detection.
šŸ’” Difficulty: hard | āœ… Correct: B

šŸ“– Explanation: By denying requests that could lead to unsafe states, the algorithm guarantees deadlock freedom. However, this conservative approach can reduce concurrency (processes wait even if resources are physically free) and potentially lead to starvation if a process's requests are repeatedly denied due to safety checks, trading off some performance/liveness for safety.

šŸ”— Related Topics (MCQs)