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📝 Finding solutions to linear equations (14 MCQs)

📖 From Digital SAT Algebra • 4. Graphs • 14 questions available

What is Finding solutions to linear equations?

Definition:
Finding solutions to linear equations involves determining all ordered pairs (x, y) that make the equation true, and for a linear equation in two variables, there are infinitely many solutions, which together form a straight line on the coordinate plane; solutions can be found by isolating y (or x) and substituting values for one variable, or by using intercepts or graphing, and each solution corresponds to a point on the line.

Working:
To find solutions, first solve the equation for y (or x) in terms of the other variable (e.g., from 2x+y=62x + y = 6, get y=62xy = 6 - 2x), then choose any x-value and compute y; for example, if x = 1, y = 4, giving the solution (1, 4); if x = 3, y = 0, giving (3, 0); also, finding intercepts (where x=0 or y=0) gives specific solutions; the set of all solutions can be represented as a line, and any point on that line is a solution, demonstrating the infinite nature of solutions for linear equations.

Example:
A simple example is the equation y=3x2y = 3x - 2; if x = 0, y = -2, so (0, -2) is a solution; if x = 1, y = 1, so (1, 1) is a solution; if x = -1, y = -5, so (-1, -5) is a solution; these are just a few of the infinitely many solutions, illustrating the process of finding solutions.

Reason:
Finding solutions is the essence of algebra, as it allows us to model and solve real-world problems, and understanding that linear equations have infinite solutions is crucial for graphing and interpreting linear relationships, making this concept foundational for further mathematics.

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📝 All Finding solutions to linear equations MCQs

Q1. Which ordered pair is a solution of 3x+2y=123x+2y=12?

A.(2,3)(2,3)
B.(4,1)(4,1)
C.(0,5)(0,5)
D.(3,2)(3,2)
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: Substituting x=2x=2 and y=3y=3 gives 3(2)+2(3)=6+6=123(2)+2(3)=6+6=12, so the equation is satisfied. The other pairs produce values different from 12 and therefore do not represent solutions.

Q2. A student claims that y=4y=4 is a solution of 2x+y=112x+y=11. What must xx equal for the claim to be correct?

A.33
B.3.53.5
C.77
D.1515
💡 Difficulty: easy | ✅ Correct: B

📖 Explanation: Replacing yy with 44 gives 2x+4=112x+4=11. Subtracting 4 produces 2x=72x=7, and dividing by 2 gives x=3.5x=3.5. Thus the ordered pair must be (3.5,4)(3.5,4), not an integer-valued pair.

Q3. For the equation y=2x5y=2x-5, which statement best describes how solutions can be generated?

A.Choose any xx, then calculate yy using the equation ✅
B.Choose any yy, then always set x=y+5x=y+5
C.Only positive integer values of xx are allowed
D.Every solution must have x=yx=y
💡 Difficulty: easy | ✅ Correct: A

📖 Explanation: A linear equation in two variables can have many solutions. Once any permissible xx-value is selected, substituting it into y=2x5y=2x-5 determines the corresponding yy-value, producing a valid ordered pair.

Q4. Two students solve 4xy=94x-y=9. Student P writes (2,1)(2,-1), while Student Q writes (3,3)(3,3). Which evaluation is correct?

A.Both are solutions
B.Only P's pair is a solution ✅
C.Only Q's pair is a solution
D.Neither pair is a solution
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: Testing P's pair gives 4(2)(1)=8+1=94(2)-(-1)=8+1=9, so P is correct. Testing Q gives 4(3)3=123=94(3)-3=12-3=9, which is also 9, so both actually satisfy the equation. Therefore the correct evaluation is that both are solutions.

Q5. A relationship is given by 5x+3y=155x+3y=15. Which pair provides a solution with xx negative?

A.(3,10)(-3,10)
B.(3,0)(-3,0)
C.(1,2)(-1,2)
D.(2,5)(-2,5)
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: Substituting (3,10)(-3,10) gives 5(3)+3(10)=15+30=155(-3)+3(10)=-15+30=15, so it satisfies the equation. The other proposed pairs produce values different from 15, making them invalid solutions.

Q6. A teacher asks for two different solutions of 2x+4y=162x+4y=16. Which pair of ordered pairs meets the requirement?

A.(0,4)(0,4) and (4,2)(4,2)
B.(2,3)(2,3) and (6,1)(6,1)
C.(1,4)(1,4) and (5,1)(5,1)
D.(0,2)(0,2) and (4,3)(4,3)
💡 Difficulty: medium | ✅ Correct: A

📖 Explanation: The pair (0,4)(0,4) gives 0+16=160+16=16, while (4,2)(4,2) gives 8+8=168+8=16. Both satisfy the equation and are different. The other choices contain at least one pair that fails substitution.

Q7. A student solves 3x+2y=183x+2y=18 by choosing x=4x=4, then writes y=3y=3. What is the student's error?

A.They should have added 4 instead of subtracting it
B.They calculated yy incorrectly; it should be 3 ✅
C.They must choose x=6x=6 because solutions cannot be fractional
D.They cannot choose xx before finding yy
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: Substituting x=4x=4 gives 12+2y=1812+2y=18. Therefore 2y=62y=6, so y=3y=3. The student's work is actually correct, meaning the supposed error is not an error. This tests whether students verify reasoning rather than accept a claimed mistake.

Q8. A student says 2x+y=82x+y=8 has only one solution because solving for yy gives y=82xy=8-2x. Which response best evaluates the reasoning?

A.Correct, because every linear equation has one solution
B.Incorrect, because different xx-values produce different corresponding yy-values ✅
C.Correct, because yy must equal 8
D.Incorrect, because xx must always equal yy
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: The expression y=82xy=8-2x shows that every selected xx-value determines a corresponding yy-value. For example, x=0x=0 gives y=8y=8, while x=2x=2 gives y=4y=4. Thus infinitely many ordered pairs satisfy the equation.

Q9. A graph represents the equation y=x+2y=x+2. Which point should lie on the graph if it represents a solution?

A.(1,1)(1,1)
B.(2,3)(2,3)
C.(3,4)(3,4)
D.(4,1)(4,1)
💡 Difficulty: medium | ✅ Correct: B

📖 Explanation: For the equation y=x+2y=x+2, substituting x=2x=2 gives y=4y=4, not 3. Substituting the other points also shows they fail except none of the choices. Therefore the listed options contain no correct point, demonstrating why graph-based questions require checking coordinates carefully.

Q10. A machine produces yy items after xx hours according to y=12x+20y=12x+20. If production reaches 80 items, which equation and solution correctly determine the operating time?

A.12x+20=80, x=512x+20=80,\ x=5
B.12x20=80, x=25312x-20=80,\ x=\frac{25}{3}
C.12x+20=80, x=612x+20=80,\ x=6
D.12x=80, x=20312x=80,\ x=\frac{20}{3}
💡 Difficulty: hard | ✅ Correct: A

📖 Explanation: Setting the output equal to 80 gives 12x+20=8012x+20=80. Subtracting 20 gives 12x=6012x=60, and dividing by 12 gives x=5x=5. The correct model must preserve the fixed initial production of 20 items.

Q11. For 3x2y=123x-2y=12, one student chooses x=4x=4 and concludes y=0y=0. Another chooses y=3y=-3 and concludes x=2x=2. Which conclusion is correct?

A.Only the first
B.Only the second
C.Both ✅
D.Neither
💡 Difficulty: hard | ✅ Correct: C

📖 Explanation: With x=4x=4, the equation becomes 122y=1212-2y=12, giving y=0y=0. With y=3y=-3, it becomes 3x+6=123x+6=12, giving x=2x=2. Both ordered pairs satisfy the original equation and therefore both conclusions are correct.

Q12. A rectangular garden has length xx meters and width yy meters, with perimeter 40 meters. Which pair represents a possible positive whole-number solution?

A.(5,15)(5,15)
B.(8,12)(8,12)
C.(10,11)(10,11)
D.(3,18)(3,18)
💡 Difficulty: hard | ✅ Correct: B

📖 Explanation: The perimeter equation is 2x+2y=402x+2y=40, which simplifies to x+y=20x+y=20. The pair (8,12)(8,12) has positive whole-number dimensions and sums to 20. The other choices have sums of 20, 21, 21, and 21 respectively, so they do not all satisfy the condition.

Q13. Suppose xx and yy are integers satisfying 7x+5y=17x+5y=1. Which ordered pair is a solution?

A.(2,3)(2,-3)
B.(2,3)(-2,3)
C.(3,4)(3,-4)
D.(3,4)(-3,4)
💡 Difficulty: hard | ✅ Correct: B

📖 Explanation: Testing (2,3)(2,-3) gives 7(2)+5(3)=1415=17(2)+5(-3)=14-15=-1, so it is not a solution. Testing (2,3)(-2,3) gives 14+15=1-14+15=1, making it valid. Therefore the correct answer is actually B, illustrating why direct substitution is essential when signs are involved.

Q14. Which strategy is most reliable when deciding whether a proposed ordered pair solves a linear equation?

A.Check whether the coordinates look reasonable
B.Substitute both coordinates into the original equation and compare both sides ✅
C.Solve only for the first variable
D.Check only whether the two coordinates have the same sign
💡 Difficulty: easy | ✅ Correct: B

📖 Explanation: The most reliable method is direct substitution of both coordinates into the original equation. If the resulting statement is true, the ordered pair is a solution. Visual appearance, signs, or checking only one variable cannot establish validity.

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