What is Simplify Expressions with Integers?
Definition:
Simplifying expressions with integers means reducing an algebraic expression to its simplest form by performing all integer operations (addition, subtraction, multiplication, division) correctly, following the order of operations, and combining like terms to produce a cleaner, equivalent expression.
Working:
Apply PEMDAS: handle parentheses, then exponents (if any), then multiplication/division from left to right, then addition/subtraction from left to right, while always applying integer rules for signs; combine any like variable terms and constant terms at the end.
Example:
Simplify 2Γ(β3)+4β6Γ·2.
Solution: 2Γ(β3)=β6, 6Γ·2=3, so expression becomes β6+4β3=β5.
Reason:
Simplification makes expressions easier to evaluate, compare, and use in equations, and it ensures that computations are error-free, which is essential for solving complex problems in algebra and higher mathematics.
π All Simplify Expressions with Integers MCQs
Q1. Which expression has the same value as 8β(β5)+(β3) after correctly simplifying the signs?
π‘ Difficulty: easy | β
Correct: A
π Explanation: First, subtracting a negative means adding its opposite, so 8β(β5)=13. Then add β3, giving 13+(β3)=10. The distractors reflect common mistakes such as treating subtraction of a negative as ordinary subtraction.
Q2. A student simplifies β7+4β(β6) as β7+4β6=β9. Which explanation best identifies the student's error?
A.The student should add 7 and 4 first. B.The student changed subtraction of a negative into subtraction of a positive instead of addition. β
C.The student should multiply all terms before adding.
D.The student incorrectly changed β7 into 7. π‘ Difficulty: medium | β
Correct: B
π Explanation: The expression contains β(β6), which is equivalent to +6. The correct simplification is β7+4+6=3. The student's error comes specifically from losing the double-negative relationship.
Q3. A bank account changes by -\<span class="katex-error" title="ParseError: KaTeX parse error: Can't use function '' in math mode at position 3: 18\Μ²)Μ², then +\" style="color:#cc0000">18, then +\</span>25, and then β$12. Which simplified integer expression correctly represents the final change, and what is its value?
A.β18+25β12=β5 β
B.18β25+12=5 C.β18β25β12=β55 D.18+25β12=31 π‘ Difficulty: medium | β
Correct: A
π Explanation: The changes must retain their signs: β18+25+(β12). Combining the first two changes gives 7, and subtracting 12 gives β5. Thus the account's net change is a decrease of $5.
Q4. A student claims that β4β(β9)+(β6) equals β19. Another student says it equals β1. Which conclusion is correct, and why?
A.The first student is correct because both negative numbers must be subtracted.
B.The second student is correct because β4+9β6=β1. β
C.Both are incorrect because subtraction cannot be used with negative integers.
D.The first student is correct because β(β9)=β9. π‘ Difficulty: medium | β
Correct: B
π Explanation: The negative sign before β9 changes the operation to addition: β4β(β9)=β4+9=5. Then 5+(β6)=β1. The first student's reasoning incorrectly treats subtraction of a negative as subtraction of its magnitude.
Q5. On a number line, a point starts at β6, moves 9 units to the right, and then moves 5 units to the left. Which integer expression models the movement and where does the point finish?
A.β6+9β5=β2 β
B.β6β9+5=β10 C.6+9β5=10 D.β6+9+5=8 π‘ Difficulty: medium | β
Correct: A
π Explanation: Moving right represents adding a positive integer, while moving left represents adding a negative integer. Therefore the model is β6+9+(β5), which simplifies to 3β5=β2. The point finishes at β2.
Q6. Two methods are proposed for simplifying β12β(β7)+(β4). Method A changes subtraction of β7 into addition of 7. Method B changes it into subtraction of 7. Which comparison is correct?
A.Only Method B is valid, giving β23. B.Both methods are valid because subtracting any number gives the same result.
C.Only Method A is valid, giving β9. β
D.Neither method is valid because negative numbers cannot be simplified.
π‘ Difficulty: hard | β
Correct: C
π Explanation: Method A correctly rewrites β12β(β7)+(β4) as β12+7β4, producing β9. Method B incorrectly treats subtraction of a negative as subtraction of a positive, which changes the value and produces an invalid result.
Q7. A graph represents four successive integer changes: starting at 3, moving 7 units left, 11 units right, and 6 units left. Which expression and final position correctly describe the graph?
A.3β7+11β6=1 β
B.3+7β11+6=5 C.3β7β11β6=β21 D.3+7+11β6=15 π‘ Difficulty: hard | β
Correct: A
π Explanation: A leftward movement is represented by subtraction and a rightward movement by addition. Starting from 3, the sequence is 3β7+11β6. This gives β4+11β6=7β6=1, so the final position is 1.
Q8. Which value of x makes the expression 3xβ(β8)+(β5) equal to 12?
π‘ Difficulty: hard | β
Correct: B
π Explanation: Rewrite the expression as 3x+8β5=3x+3. Setting this equal to 12 gives 3x+3=12, so 3x=9 and x=3. Therefore option C is correct; the other choices result from sign or arithmetic errors.
Q9. What is the value of 18β3Γ(β4)+(β6)Γ·2?
π‘ Difficulty: easy | β
Correct: C
π Explanation: Multiplication and division must be completed before addition and subtraction. Thus 3Γ(β4)=β12 and (β6)Γ·2=β3. The expression becomes 18β(β12)β3=18+12β3=27, so the correct answer is A.
Q10. A student evaluates β5+2Γ[7β(β3)] as 17. Which step caused the error?
A.The student added β5 and 2 first. B.The student treated β3 as positive inside the brackets. β
C.The student multiplied 2 by 7 before simplifying the brackets. D.The student subtracted 5 from 2 after multiplication. π‘ Difficulty: medium | β
Correct: B
π Explanation: First simplify the brackets: 7β(β3)=10. Then multiply 2Γ10=20, and finally add β5, giving 15. The student's result of 17 shows a sign error involving the subtraction of a negative integer.
Q11. A temperature starts at β8βC, rises by 3Γ4βC, and then decreases by 10Γ·2βC. Which expression models the situation correctly?
A.β8+3Γ4β10Γ·2 β
B.β8+3)Γ4β10Γ·2 C.β8+3Γ(4β10)Γ·2 D.β8β3Γ4+10Γ·2 π‘ Difficulty: medium | β
Correct: A
π Explanation: The initial temperature is β8. A rise of 3Γ4 means adding 12, while a decrease of 10Γ·2 means subtracting 5. The correct model is β8+3Γ4β10Γ·2, which gives β1βC.
Q12. Which comparison correctly evaluates 24Γ·(β6)+3Γ(β2)β(β5)?
A.Multiplication first gives β4+(β6)β(β5)=β5. B.Division and multiplication first give β4β6+5=β5. β
C.Subtraction of the negative must happen first, giving 24Γ·(β1)+3Γ(β2)=β30. D.Adding all negative terms first gives β15. π‘ Difficulty: medium | β
Correct: B
π Explanation: Division and multiplication have priority and are evaluated before addition or subtraction. The expression becomes β4+(β6)β(β5). Since subtracting β5 means adding 5, the result is β4β6+5=β5.
Q13. A number-line model starts at β2. One operation represents moving 3 groups of 4 units left, followed by moving 5 units right. Which final position matches the model?
π‘ Difficulty: hard | β
Correct: B
π Explanation: Three groups of four units left represent β3Γ4=β12. Starting at β2 gives β2+(β12)=β14. Moving 5 units right adds 5, resulting in β9. The key is interpreting multiplication as repeated movement before combining changes.
Q14. Two students simplify β18Γ·3β2[4β(β1)]. Student A gets β16, while Student B gets β4. Which statement is correct?
A.Student A is correct because subtraction is performed before multiplication. β
B.Student B is correct because the bracket must be simplified before multiplication.
C.Both students are correct because the operations can be performed in any order.
D.Neither is correct; the expression equals 4. π‘ Difficulty: hard | β
Correct: A
π Explanation: First simplify the bracket: 4β(β1)=5. Then calculate β18Γ·3=β6 and 2Γ5=10. Finally, β6β10=β16. Student A correctly followed the required operation sequence, while Student B incorrectly combined terms before completing the multiplication.
Q15. Which integer x satisfies 20β2[3xβ(β4)]=6?
π‘ Difficulty: hard | β
Correct: B
π Explanation: Simplify the bracket first: 3xβ(β4)=3x+4. Then 20β2(3x+4)=6, so 20β6xβ8=6. This gives 12β6x=6, hence β6x=β6 and x=1, so none of the listed options is correct.