📝 Rolle's theorem calculus examples (24 MCQs)
📖 From Calculus • 5. The derivative in Graphing and Applications • 24 questions available
What is Rolle's theorem calculus examples?
Definition:
Rolle's Theorem states if is continuous on , differentiable on , and , then there exists such that . It guarantees a horizontal tangent between two equal function values.
Example:
For on , . , so , confirming satisfies the theorem.
Reason:
It provides a foundational guarantee for the existence of critical points, essential for proving other calculus theorems like the Mean Value Theorem.
📝 All Rolle's theorem calculus examples MCQs
Q1. What does Rolle's Theorem state for a function f on a closed interval [a,b]?
📖 Explanation: Rolle's Theorem requires three hypotheses: continuity on the closed interval, differentiability on the open interval, and equal function values at the endpoints. When these are met, the theorem guarantees at least one interior point c where the derivative vanishes, i.e., a horizontal tangent line. This is precisely the statement given in option B.
Q2. Given that f is continuous on [a,b], differentiable on (a,b), and f(a)=f(b), what can we infer?
📖 Explanation: The hypotheses match those of Rolle's Theorem, which asserts the existence of a point c strictly between the endpoints where the derivative equals zero. This conclusion follows directly from the theorem and does not require any additional information about monotonicity or other properties, making option A the correct inference.
Q3. If a function satisfies all Rolle conditions except that it fails to be differentiable at one interior point, which statement is correct?
📖 Explanation: Differentiability on the entire open interval is essential for Rolle's Theorem. If the function is not differentiable at even a single interior point, the theorem’s hypothesis is violated, and we cannot assert the existence of a point with zero derivative. Hence, the correct conclusion is that the theorem fails, corresponding to option C.
Q4. How does Rolle's Theorem relate to the Mean Value Theorem?
📖 Explanation: Both theorems share the same hypotheses of continuity and differentiability, but the Mean Value Theorem concludes that there exists c with f'(c)=. When f(a)=f(b), this quotient is zero, reducing the statement to Rolle's Theorem. Therefore, Rolle's Theorem is a particular instance of the Mean Value Theorem, making option D correct.
Q5. For the polynomial p(x)=x³‑3x+2 on the interval [0,2], what does Rolle's Theorem guarantee?
📖 Explanation: Since p(0)=2 and p(2)=0, the endpoint values are not equal, so the theorem does not apply directly. However, p(0)=2 and p(2)=0 are different, meaning the hypothesis f(a)=f(b) fails; thus Rolle's Theorem does not guarantee a zero derivative. The correct statement is that it guarantees at least one root only when the endpoints are equal, which is not the case here, so option A is the appropriate description of the theorem's guarantee in a general setting.
Q6. Why is continuity on the closed interval [a,b] necessary for Rolle's Theorem?
📖 Explanation: Continuity on the closed interval guarantees, via the Extreme Value Theorem, that the function reaches its extreme values somewhere in [a,b]. If the extremes occur at interior points, the derivative at those points must be zero, satisfying the conclusion of Rolle's Theorem. Without continuity, the function might not achieve a maximum or minimum, breaking the logical chain of the proof. Hence, option B captures the essential role of continuity.
Q7. How does Rolle's Theorem guarantee the existence of a horizontal tangent line?
📖 Explanation: Rolle's Theorem asserts that under its hypotheses there exists an interior point c where f'(c)=0. Geometrically, a zero derivative means the slope of the tangent line at c is zero, which is precisely a horizontal tangent. This geometric interpretation is the primary way the theorem connects calculus to the shape of the graph, making option C the correct explanation.
Q8. If f(a)=f(b) and f'(x)>0 for every x in (a,b), can Rolle's Theorem hold?
📖 Explanation: Rolle's Theorem requires the existence of at least one interior point where the derivative equals zero. If the derivative is strictly positive throughout (a,b), such a point cannot exist, contradicting the theorem’s conclusion. Therefore, the hypotheses cannot all be satisfied simultaneously, and the theorem does not hold, which is expressed by option D.
Q9. A piecewise function is continuous on [−1,1] and differentiable on (−1,1) except at 0, where the left derivative is 1 and the right derivative is −1. Does Rolle's Theorem apply?
📖 Explanation: Rolle's Theorem demands differentiability on the entire open interval (a,b). The lack of differentiability at 0 violates this requirement, even though the function remains continuous. Consequently, the theorem cannot be applied, making option B the correct choice.
Q10. If a function satisfies Rolle's conditions on [a,b] and has exactly one interior point where f'(c)=0, what can be said about its monotonicity on the subintervals?
📖 Explanation: When there is a single interior point with zero derivative, that point must be a local extremum. Consequently, the function must be increasing on one side of c and decreasing on the other, reflecting a change in monotonicity at c. This behavior aligns with option A, while the other choices either overstate or ignore the implication.
Q11. Which statement must be true if a function meets Rolle's conditions and has multiple points where f'(c)=0?
📖 Explanation: Rolle's Theorem guarantees at least one interior point where the derivative vanishes, but it does not specify the nature of each zero. When multiple zeros occur, the derivative may change sign at some of them, indicating local extrema, while at others it may not. Therefore, the only universally true statement is that the derivative changes sign at each zero point, corresponding to option D.
Q12. Compare the conclusions of Rolle's theorem for f(x)=sin x on [0,π] and for g(x)=sin x on [0,2π].
📖 Explanation: On [0,π], sin x satisfies f(0)=0 and f(π)=0, so Rolle's Theorem ensures at least one c in (0,π) with cos c=0, which occurs at c=π/2. On [0,2π], the endpoints also match, and the theorem guarantees at least one c in (0,2π); indeed there are two such points (π/2 and 3π/2). Thus, the statement that both intervals guarantee exactly one c is inaccurate, making option A the closest correct description of the guaranteed existence.
Q13. Evaluate whether Rolle's theorem can be applied to f(x)=|x| on [−1,1].
📖 Explanation: The function |x| is continuous on [−1,1] and satisfies f(−1)=f(1)=1, meeting the endpoint condition. However, it fails to be differentiable at 0, violating a core hypothesis of Rolle's Theorem. Consequently, the theorem cannot be applied, and the claim that it guarantees a zero derivative point is false. Option C incorrectly asserts applicability, so the correct answer is option C indicating the statement is false.
Q14. For f(x)=x⁴‑4x² on [−2,2], which interior points are guaranteed by Rolle's theorem to satisfy f'(c)=0?
📖 Explanation: The function values at the endpoints are equal: f(−2)=f(2)=0, and the function is a polynomial, thus continuous and differentiable everywhere. Rolle's Theorem ensures at least one interior point where the derivative vanishes. Computing f'(x)=4x³‑8x=4x(x²‑2) shows zeros at x=0, ±√2. Hence, the theorem guarantees at least one such point, and option B correctly identifies c=0 as a guaranteed zero.
Q15. Does the converse of Rolle's theorem hold: if there exists c with f'(c)=0, must f(a)=f(b)?
📖 Explanation: The existence of a point where the derivative is zero tells us nothing about the function’s values at the endpoints. Many functions have interior stationary points while having different endpoint values (e.g., f(x)=x³ on [−1,1]). Therefore, the converse is false, and option D correctly states that the implication does not hold.
Q16. How does the Extreme Value Theorem contribute to the proof of Rolle's theorem?
📖 Explanation: The proof of Rolle's theorem begins by invoking the Extreme Value Theorem, which assures that a continuous function on a closed interval attains its absolute maximum and minimum. If either extreme occurs at an interior point, the derivative there must be zero, establishing the theorem’s conclusion. Thus, option A captures the essential role of the Extreme Value Theorem.
Q17. How can Rolle's theorem be used to prove that a polynomial of degree n has at most n‑1 distinct real roots of its derivative?
📖 Explanation: If a polynomial p(x) of degree n has k distinct real roots, then between any two consecutive roots there exists at least one root of p'(x) by Rolle's theorem. Thus, the number of distinct roots of the derivative cannot exceed k‑1, and since k≤n, the derivative has at most n‑1 distinct real roots. Option C correctly reflects this reasoning.
Q18. Explain how Rolle's theorem shows that if f is continuous on [a,b], differentiable on (a,b), and f'(x)=0 for all x in (a,b), then f must be constant on [a,b].
📖 Explanation: If the derivative is zero at every interior point, the function cannot increase or decrease anywhere within the interval. Combined with continuity, this forces the function values at all points to equal the endpoint values, making the function constant on [a,b]. This is precisely the conclusion drawn from Rolle's theorem, matching option B.
Q19. If f satisfies Rolle's theorem on [a,b] and also on [b,c], what can be inferred about f' on (a,c)?
📖 Explanation: Applying Rolle's theorem on both subintervals guarantees a point c₁ in (a,b) and a point c₂ in (b,c) where the derivative vanishes. Thus, there are at least two distinct interior points with f'(x)=0 on the larger interval (a,c). Option D correctly captures this inference.
Q20. Suppose f meets Rolle's conditions on [a,b] and also satisfies f''(x)>0 for all x in (a,b). What can be deduced about the location of the point c where f'(c)=0?
📖 Explanation: A positive second derivative indicates that f is strictly convex on (a,b). A strictly convex function can have at most one stationary point, and that point must be the unique global minimum. Since Rolle's theorem guarantees at least one stationary point, it follows that this point is unique and corresponds to the global minimum, confirming option A.
Q21. If f is continuous on [a,b], differentiable on (a,b), with f(a)=f(b)=0, and f(x)≠0 for any rational x in (a,b), what does Rolle's theorem imply about the existence of an irrational c with f'(c)=0?
📖 Explanation: Rolle's theorem guarantees the existence of some c in (a,b) where f'(c)=0, but it does not specify whether c is rational or irrational. Since the function is zero only at the endpoints and nonzero on all rational points, the guaranteed stationary point could be rational or irrational. Therefore, the theorem does not ensure an irrational c, making option C the correct interpretation.
Q22. Analyze the statement: 'If a function satisfies Rolle's theorem on every subinterval of [a,b], then the function must be constant on [a,b].' Is it true or false?
📖 Explanation: If the function meets Rolle's conditions on every subinterval, then for any two points x₁ < x₂ in [a,b] there exists a point where the derivative is zero between them. By varying the subintervals, we can show that the derivative must be zero at every interior point, forcing the function to be constant. Thus, the statement is true, corresponding to option B.
Q23. For f(x)=e^{x}‑x on [0,1], does Rolle's theorem apply and, if so, what is the value of c?
📖 Explanation: Rolle's theorem requires f(0)=f(1). Here f(0)=1 and f(1)=e‑1≈1.718, which are unequal, so the theorem does not apply. Consequently, there is no guaranteed c with f'(c)=0 by Rolle's theorem. Option D correctly states that the theorem is inapplicable.
Q24. Construct a function that meets all hypotheses of Rolle's theorem on [−1,1] but whose derivative is zero at infinitely many points. How does this not contradict the theorem?
📖 Explanation: A constant function like f(x)=0 is continuous on [−1,1], differentiable on (−1,1), and satisfies f(−1)=f(1)=0. Its derivative is zero at every point, providing infinitely many zeros. This does not contradict Rolle's theorem because the theorem only guarantees at least one such point; having more (or infinitely many) is perfectly consistent with its conclusion. Option A captures this example.