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πŸ“ Power functions with rational exponents (13 MCQs)

πŸ“– From Calculus β€’ 1. Basics before calculus β€’ 13 questions available

What is Power functions with rational exponents?

Definition:
Power functions with rational exponents are of the form y=xm/ny = x^{m/n}, where m/nm/n is a fraction in lowest terms, which can be interpreted as y=xmny = \sqrt[n]{x^m} or (xn)m(\sqrt[n]{x})^m, and their domains depend on whether nn is odd or even.

Example:
For y=x1/2=xy = x^{1/2} = \sqrt{x}, domain is xβ‰₯0x \geq 0; for y=x2/3y = x^{2/3}, domain is all real numbers since x23\sqrt[3]{x^2} is defined for all xx.

Reason:
These functions bridge roots and powers, allowing us to model growth like population (with fractional exponents) or geometric scaling.

4
Easy
6
Medium
3
Hard

πŸ“ All Power functions with rational exponents MCQs

Q1. Which radical notation correctly represents the function f(x)=x1/nf(x)=x^{1/n} for a positive integer nn?

A.xn\sqrt[n]{x} βœ…
B.nx{n}\sqrt{x}
C.xn\sqrt{x^{n}}
D.xnx^{n}
πŸ’‘ Difficulty: easy | βœ… Correct: A

πŸ“– Explanation: The notation xn\sqrt[n]{x} is defined as the nth root of x, which is exactly the same as raising x to the power 1/n1/n. The other choices either misplace the index or represent different powers, so option A correctly matches the given function.

Q2. Given f(x)=x4f(x)=\sqrt[4]{x} and g(x)=x2g(x)=x^{2}, which statement is true about the composition values at x=16x=16?

A.f(g(16))>g(f(16))f(g(16)) > g(f(16))
B.f(g(16))=g(f(16))f(g(16)) = g(f(16)) βœ…
C.f(g(16))<g(f(16))f(g(16)) < g(f(16))
D.Both are undefined
πŸ’‘ Difficulty: easy | βœ… Correct: B

πŸ“– Explanation: Compute g(16)=256g(16)=256; then f(g(16))=2561/4=4f(g(16))=256^{1/4}=4. Also f(16)=161/4=2f(16)=16^{1/4}=2 and g(f(16))=22=4g(f(16))=2^{2}=4. Both compositions give the same result, so the equality statement is correct.

Q3. How does the graph of y=xy=\sqrt{x} compare to the graph of y=x1/3y=x^{1/3} for xβ‰₯0x\ge 0?

A.Both are linear
B.x\sqrt{x} grows faster than x1/3x^{1/3} βœ…
C.x1/3x^{1/3} grows faster than x\sqrt{x}
D.They coincide for all xβ‰₯0x\ge0
πŸ’‘ Difficulty: easy | βœ… Correct: B

πŸ“– Explanation: For x>1x>1, the exponent 0.5 (square root) yields larger values than the exponent 0.333… (cube root). Near zero both approach zero, but the square‑root curve rises more quickly, making option B the accurate comparison.

Q4. If a power function has exponent p=1/np=1/n with nn even, which must be true about its domain?

A.All real numbers
B.Only non‑negative numbers βœ…
C.Only negative numbers
D.No real numbers
πŸ’‘ Difficulty: easy | βœ… Correct: B

πŸ“– Explanation: When nn is even, the nth root of a negative number is not real, so the function is defined only for xβ‰₯0x\ge0. Hence the domain consists of non‑negative real numbers, matching option B.

Q5. Suppose h(x)=x1/5h(x)=x^{1/5}. Which statement correctly describes the effect of squaring the input before applying hh versus applying hh before squaring, for any positive xx?

A.h(x2)=[h(x)]2h(x^{2}) = [h(x)]^{2} βœ…
B.h(x2)>[h(x)]2h(x^{2}) > [h(x)]^{2}
C.h(x2)<[h(x)]2h(x^{2}) < [h(x)]^{2}
D.Equality holds only when x=1x=1
πŸ’‘ Difficulty: medium | βœ… Correct: A

πŸ“– Explanation: h(x2)=(x2)1/5=x2/5h(x^{2})=(x^{2})^{1/5}=x^{2/5}. Meanwhile [h(x)]2=(x1/5)2=x2/5[h(x)]^{2}=(x^{1/5})^{2}=x^{2/5}. The two expressions are identical for every positive xx, confirming the equality in option A.

Q6. Consider the functions f(x)=x1/2f(x)=x^{1/2} and g(x)=x2/3g(x)=x^{2/3}. For x>1x>1, which function yields larger output values?

A.f(x)f(x) for all x>1x>1
B.g(x)g(x) for all x>1x>1 βœ…
C.They are equal
D.Depends on whether xx is an integer
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: The exponent of gg is 2/3β‰ˆ0.6672/3\approx0.667, larger than the exponent 1/2=0.51/2=0.5 of ff. For numbers greater than one, a larger exponent produces a larger value, so g(x)g(x) is greater for every x>1x>1.}

Q7. When the exponent pp in y=xpy=x^{p} is a reciprocal of an odd integer, how does the function behave for negative inputs?

A.Undefined
B.Produces positive outputs only
C.Mirrors the positive‑x graph
D.Produces negative outputs mirroring the positive‑x graph βœ…
πŸ’‘ Difficulty: medium | βœ… Correct: D

πŸ“– Explanation: If the denominator is odd, the root of a negative number is defined and remains negative, giving the function odd symmetry. Thus the graph for negative xx is the mirror image of the positive side, reflected across the origin, as described in option D.

Q8. Let k(x)=x1/6k(x)=x^{1/6}. Which inequality correctly represents the relationship between k(64)k(64) and k(8)2k(8)^{2}?

A.k(64)>k(8)2k(64) > k(8)^{2}
B.k(64)=k(8)2k(64) = k(8)^{2} βœ…
C.k(64)<k(8)2k(64) < k(8)^{2}
D.No comparison possible because one side is undefined
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: k(64)=641/6=2k(64)=64^{1/6}=2. Meanwhile k(8)=81/6=21/2=2k(8)=8^{1/6}=2^{1/2}=\sqrt{2}; squaring gives (2)2=2(\sqrt{2})^{2}=2. Both sides equal 2, making the equality statement correct.

Q9. Which statement is true about the derivative of f(x)=x1/nf(x)=x^{1/n} for a positive integer nn?

A.f&#039;(x)=\frac{1}{n}x^{1/n-1} βœ…
B.f&#039;(x)=\frac{1}{n}x^{1/n+1}
C.f&#039;(x)=n x^{n-1}
D.The derivative does not exist for any xx
πŸ’‘ Difficulty: medium | βœ… Correct: A

πŸ“– Explanation: Using the power rule, ddxxp=p xpβˆ’1\frac{d}{dx}x^{p}=p\,x^{p-1}. Substituting p=1/np=1/n gives f&#039;(x)=\frac{1}{n}x^{1/n-1}, which matches option A. The other choices misuse the rule or claim non‑existence incorrectly.

Q10. If a function y=xpy=x^{p} with p=1/4p=1/4 is reflected over the line y=xy=x, which function describes the reflected graph?

A.y=x4y=x^{4} βœ…
B.y=x4y=\sqrt[4]{x}
C.y=x1/2y=x^{1/2}
D.y=x2y=x^{2}
πŸ’‘ Difficulty: medium | βœ… Correct: A

πŸ“– Explanation: Reflecting over y=xy=x swaps the variables, turning y=x1/4y=x^{1/4} into x=y1/4x=y^{1/4}. Solving for yy yields y=x4y=x^{4}. Hence the reflected graph is represented by y=x4y=x^{4}, which is option A.

Q11. For f(x)=x1/3f(x)=x^{1/3} and g(x)=x2g(x)=x^{2}, determine which composition yields a larger value at x=0.001x=0.001.

A.f(g(x))f(g(x)) is larger
B.g(f(x))g(f(x)) is larger
C.They are equal βœ…
D.Both are zero
πŸ’‘ Difficulty: hard | βœ… Correct: C

πŸ“– Explanation: Compute g(0.001)=10βˆ’6g(0.001)=10^{-6}; then f(g)=(10βˆ’6)1/3=10βˆ’2=0.01f(g)= (10^{-6})^{1/3}=10^{-2}=0.01. Also f(0.001)=10βˆ’1=0.1f(0.001)=10^{-1}=0.1; g(f)=0.12=0.01g(f)=0.1^{2}=0.01. Both compositions give 0.01, so the values are equal, confirming option C.

Q12. Consider f(x)=x1/5f(x)=x^{1/5} and h(x)=x3/5h(x)=x^{3/5}. Which correctly describes the ratio h(x)f(x)\frac{h(x)}{f(x)} for x>0x>0?

A.It equals x2/5x^{2/5} βœ…
B.It equals x1/5x^{1/5}
C.It equals x3/5x^{3/5}
D.It is constant equal to 1
πŸ’‘ Difficulty: hard | βœ… Correct: A

πŸ“– Explanation: Dividing the two power functions gives x3/5/x1/5=x(3/5βˆ’1/5)=x2/5x^{3/5}/x^{1/5}=x^{(3/5-1/5)}=x^{2/5}. Therefore the ratio simplifies to x2/5x^{2/5}, matching option A.

Q13. A student claims that the graph of y=x1/3y=x^{1/3} is a horizontal stretch of the graph of y=x1/2y=x^{1/2}. Which reasoning correctly evaluates this claim?

A.True, because both are root functions
B.False; the two graphs differ in curvature and cannot be obtained by a simple stretch βœ…
C.True; a stretch factor of x1/6x^{1/6} converts one into the other
D.False; only a vertical stretch could relate them
πŸ’‘ Difficulty: hard | βœ… Correct: B

πŸ“– Explanation: Although both are root functions, their exponents (1/3 vs 1/2) give distinct curvature. No constant horizontal stretch can transform one graph into the other; the shapes are fundamentally different, so the claim is false as stated in option B.

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