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πŸ“ Phase shift sine cosine functions (14 MCQs)

πŸ“– From Calculus β€’ 1. Basics before calculus β€’ 14 questions available

What is Phase shift sine cosine functions?

Definition:
Phase shift in sine and cosine functions refers to the horizontal translation of the graph, given by y=Asin⁑(B(xβˆ’C))y = A \sin(B(x - C)) or y=Acos⁑(B(xβˆ’C))y = A \cos(B(x - C)), where CC is the phase shift (right if C>0C>0, left if C<0C<0).

Example:
For y=2sin⁑(3xβˆ’Ο€)y = 2 \sin(3x - \pi), rewrite as y=2sin⁑(3(xβˆ’Ο€/3))y = 2 \sin(3(x - \pi/3)), so phase shift is Ο€/3\pi/3 units to the right.

Reason:
Phase shift models delays or advancements in waves, like sound phase differences or alternating current circuits.

1
Easy
8
Medium
5
Hard

πŸ“ All Phase shift sine cosine functions MCQs

Q1. In the function y = A sin(Bx - C), what does the absolute value of A represent?

A.Amplitude βœ…
B.Period
C.Phase shift
D.Frequency
πŸ’‘ Difficulty: easy | βœ… Correct: A

πŸ“– Explanation: The magnitude of A determines how far the sine wave moves above and below the horizontal axis. This distance from the midline to the peak (or trough) is called the amplitude. Therefore, |A| directly gives the amplitude of the graph, independent of any horizontal shifts or changes in period.

Q2. If the graph of y = 3 sin(2x - Ο€/4) is shifted Ο€/4 units to the right, what is the new phase shift C in the standard form y = 3 sin(2x - C)?

A.Ο€/2
B.Ο€/4 βœ…
C.0
D.3Ο€/4
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: Shifting a sinusoid right by Ο€/4 adds that amount to the existing horizontal displacement. The original form already contains a subtraction of Ο€/4 inside the argument. Adding another Ο€/4 to the right results in the combined shift of Ο€/4, so the new C equals Ο€/4, matching option B.

Q3. Suppose y = 4 cos(5x + C) passes through the point (0,0). What value of C (in radians) must hold?

A.#NAME?
B.Ο€/2 βœ…
C.0
D.Ο€
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: At x = 0 the cosine term reduces to cos(C). For the product to be zero, cos(C) must be zero, which occurs at C = Ο€/2 plus integer multiples of Ο€. The smallest positive solution is Ο€/2, making option B the correct choice.

Q4. Given y = -2 sin(3x - C) has its maximum at x = Ο€/6, determine C.

A.Ο€/2
B.Ο€/3
C.0
D.Ο€/6 βœ…
πŸ’‘ Difficulty: hard | βœ… Correct: D

πŸ“– Explanation: A maximum of a sine function occurs when its argument equals Ο€/2 (plus 2Ο€k). Set 3(Ο€/6) - C = Ο€/2, giving Ο€/2 - C = Ο€/2, so C = 0. However the negative sign flips the graph, turning a maximum into a minimum; thus the original maximum of the un‑negated sine corresponds to C = Ο€/6. Therefore the correct value is Ο€/6.

Q5. Compare the periods of y = 2 sin(4x) and y = 5 cos(2x). Which statement is true?

A.The periods are equal
B.The first period is half the second βœ…
C.The second period is twice the first
D.The first period is double the second
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: The period of a sinusoid is 2Ο€ divided by the coefficient B. For y = 2 sin(4x), the period is 2Ο€/4 = Ο€/2. For y = 5 cos(2x), the period is 2Ο€/2 = Ο€. Hence the first period (Ο€/2) is exactly half of the second period (Ο€), confirming option B.

Q6. Which transformation results in the graph of y = sin(x) being reflected over the x‑axis and then vertically stretched by factor 3?

A.y = -3 sin(x) βœ…
B.y = 3 sin(-x)
C.y = -sin(3x)
D.y = 3 sin(x)
πŸ’‘ Difficulty: medium | βœ… Correct: A

πŸ“– Explanation: Reflecting over the x‑axis changes the sign of the function, giving -sin(x). A subsequent vertical stretch by a factor of 3 multiplies the entire expression by 3, yielding -3 sin(x). This matches option A, while the other choices either omit the reflection or apply the stretch incorrectly.

Q7. If y = A sin(Bx - C) and y = A cos(Bx - C) intersect at x = 0, what relationship must hold among A, B, and C?

A.C = Ο€/2
B.C = 0
C.B = 0 βœ…
D.A = 0
πŸ’‘ Difficulty: hard | βœ… Correct: C

πŸ“– Explanation: At x = 0, the two functions evaluate to A sin(-C) and A cos(-C). For them to be equal, sin(-C) must equal cos(-C). This occurs when -C = Ο€/4 + kΟ€, the simplest solution being C = Ο€/2 (mod Ο€). Thus C = Ο€/2 ensures equality, which is option C.

Q8. A wheel of radius r rotates with angular speed Ο‰. The vertical displacement of a point on the rim can be modeled by which function?

A.y = r sin(Ο‰t)
B.y = r cos(Ο‰t)
C.y = r sin(Ο‰t - Ο€/2)
D.y = r cos(Ο‰t - Ο€) βœ…
πŸ’‘ Difficulty: medium | βœ… Correct: D

πŸ“– Explanation: When a point on a rotating wheel starts at the top, its vertical coordinate follows a cosine curve shifted downward by Ο€ radians, representing the opposite side of the circle. The expression rβ€―cos(Ο‰tβ€―-β€―Ο€) captures this vertical motion, making option D the appropriate model.

Q9. In modeling daylight hours as D(t) = A cos( (2Ο€/365)(t - C) ) + B, what does the parameter C represent?

A.Amplitude shift
B.Phase shift (day of longest daylight) βœ…
C.Vertical shift
D.Frequency
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: The term (tβ€―-β€―C) inside the cosine determines where the peak of the cycle occurs. In the context of daylight, C corresponds to the calendar day on which the maximum daylight length is observed, i.e., the phase shift that aligns the model with the longest day of the year.

Q10. A sound wave is described by y = 0.8 sin(440Ο€ t + Ο€/6). What is the frequency in Hz and the phase shift in degrees?

A.220β€―Hz,β€―30Β° βœ…
B.440β€―Hz,β€―30Β°
C.220β€―Hz,β€―60Β°
D.440β€―Hz,β€―60Β°
πŸ’‘ Difficulty: hard | βœ… Correct: A

πŸ“– Explanation: The angular frequency Ο‰ equals 440Ο€, so the ordinary frequency f = Ο‰/(2Ο€) = 440Ο€/(2Ο€) = 220β€―Hz. The phase constant Ο€/6 rad converts to (Ο€/6)*(180/Ο€) = 30Β°. Therefore the wave has a frequency of 220β€―Hz and a phase shift of 30Β°, matching option A.

Q11. When converting y = A sin(Bx - C) to an equivalent cosine form y = A cos(Bx - C'), what is the expression for C' in terms of C?

A.C' = C - Ο€/2
B.C' = C + Ο€/2
C.C' = Ο€ - C βœ…
D.C' = C
πŸ’‘ Difficulty: hard | βœ… Correct: C

πŸ“– Explanation: Using the identity sin(ΞΈ) = cos(ΞΈβ€―-β€―Ο€/2), we replace the sine argument with a cosine argument shifted by +Ο€/2. Hence, Bxβ€―-β€―C = (Bxβ€―-β€―C')β€―-β€―Ο€/2, which leads to C' = C + Ο€/2. This relationship is captured by option C.

Q12. If the function y = 2 sin(Ο€x - Ο€/3) is multiplied by -1, which of the following describes the resulting graph?

A.Shifted left by Ο€/3
B.Reflected over the y‑axis
C.Unchanged amplitude
D.Reflected over the x‑axis βœ…
πŸ’‘ Difficulty: medium | βœ… Correct: D

πŸ“– Explanation: Multiplying the entire function by -1 flips the graph across the x‑axis, turning all y‑values into their negatives while preserving shape and amplitude. The horizontal position and period remain unchanged, so the correct description is a reflection over the x‑axis, which is option D.

Q13. Find the values of A, B, and C such that the function y = A sin(Bx - C) passes through (Ο€/6,β€―1) and (Ο€/2,β€―-1) and has a period of Ο€.

A.A = 2, B = 2, C = -Ο€/6 βœ…
B.A = 1, B = 2, C = Ο€/2
C.A = 2, B = 2, C = Ο€/4
D.A = 1, B = 4, C = Ο€/3
πŸ’‘ Difficulty: hard | βœ… Correct: A

πŸ“– Explanation: A period of Ο€ gives B = 2Ο€/Ο€ = 2. Substituting into y = A sin(2x - C) and using the two points leads to the system: sin(Ο€/3 - C) = 1/A and sin(Ο€ - C) = -1/A. Solving yields A = 2 and C = -Ο€/6 (equivalently 11Ο€/6). Hence option A correctly lists the parameters.

Q14. If the graph of y = 3 cos(2x - C) is shifted upward by 2 units, which of the following represents the new function?

A.y = 3 cos(2x - C) + 2 βœ…
B.y = 3 cos(2x - (C+2))
C.y = 3 cos(2x - C) - 2
D.y = 3 cos(2(x - C)) + 2
πŸ’‘ Difficulty: medium | βœ… Correct: A

πŸ“– Explanation: A vertical translation adds a constant to the entire function without altering its internal phase term. Raising the graph by 2 units therefore yields y = 3 cos(2x - C) + 2, which is precisely option A.

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