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πŸ“ One to one functions and invertibility (12 MCQs)

πŸ“– From Calculus β€’ 1. Basics before calculus β€’ 12 questions available

What is One to one functions and invertibility?

Definition:
A one-to-one function (injective) maps distinct inputs to distinct outputs, i.e., f(a)=f(b)f(a) = f(b) implies a=ba = b, making it invertible over its range, with a unique inverse function defined everywhere on that range.

Example:
f(x)=3xβˆ’1f(x)=3x-1 is one-to-one because if 3aβˆ’1=3bβˆ’13a-1=3b-1, then a=ba=b; hence it is invertible, with inverse fβˆ’1(x)=(x+1)/3f^{-1}(x) = (x+1)/3.

Reason:
One-to-one property is the key to invertibility, allowing for reversible processes in mathematics, cryptography, and data encoding.

4
Easy
5
Medium
3
Hard

πŸ“ All One to one functions and invertibility MCQs

Q1. Which of the following best describes an increasing function on an interval?

A.For any x1<x2x_1<x_2, f(x1)>f(x2)f(x_1)>f(x_2).
B.For any x1<x2x_1<x_2, f(x1)<f(x2)f(x_1)<f(x_2). βœ…
C.The function satisfies f&#039;(x)=0 everywhere.
D.The function is symmetric about the y‑axis.
πŸ’‘ Difficulty: easy | βœ… Correct: B

πŸ“– Explanation: An increasing function must satisfy the inequality f(x1)<f(x2)f(x_1)<f(x_2) whenever the input satisfies x1<x2x_1<x_2. Option B states exactly this condition, making it the correct definition. The other options either reverse the inequality or describe unrelated properties.

Q2. Suppose ff is strictly increasing on its domain and has an inverse fβˆ’1f^{-1}. Which of the following must be true for any y1<y2y_1<y_2 in the range of ff?

A.fβˆ’1(y1)>fβˆ’1(y2)f^{-1}(y_1) > f^{-1}(y_2)
B.fβˆ’1(y1)=fβˆ’1(y2)f^{-1}(y_1) = f^{-1}(y_2)
C.fβˆ’1(y1)<fβˆ’1(y2)f^{-1}(y_1) < f^{-1}(y_2) βœ…
D.No relationship can be deduced.
πŸ’‘ Difficulty: easy | βœ… Correct: C

πŸ“– Explanation: Because ff is strictly increasing, its inverse preserves order: smaller outputs correspond to smaller inputs. Hence if y1<y2y_1<y_2 then the pre‑images satisfy fβˆ’1(y1)<fβˆ’1(y2)f^{-1}(y_1)<f^{-1}(y_2). This logical consequence rules out the other choices.

Q3. Given two functions f(x)=2x+3f(x)=2x+3 and g(x)=2xβˆ’5g(x)=2x-5, which statement correctly compares their monotonicity?

A.Both are decreasing because the coefficient of xx is positive.
B.Both are increasing because the coefficient of xx is positive. βœ…
C.ff is increasing while gg is decreasing.
D.Neither is monotonic.
πŸ’‘ Difficulty: easy | βœ… Correct: B

πŸ“– Explanation: The slope of each linear function is the coefficient of xx. Since both coefficients are +2+2, each line rises as xx increases, making both functions strictly increasing. The other options misinterpret the sign of the slope or claim non‑monotonic behavior incorrectly.

Q4. If a function h(x)=xh(x)=\sqrt{x} is defined for xβ‰₯0x\ge0, what is its inverse hβˆ’1(x)h^{-1}(x)?

A.x2x^{2} βœ…
B.x\sqrt{x}
C.1/x1/x
D.ln⁑x\ln x
πŸ’‘ Difficulty: easy | βœ… Correct: A

πŸ“– Explanation: To find the inverse, swap yy and xx: x=yx=\sqrt{y} implies y=x2y=x^{2}. Because the original domain is xβ‰₯0x\ge0, the inverse is defined for xβ‰₯0x\ge0 as x2x^{2}. The other options either reproduce the original function or represent unrelated operations.

Q5. Consider a function pp that is strictly decreasing on [βˆ’2,4][-2,4]. Which of the following statements about its inverse pβˆ’1p^{-1} is necessarily true?

A.The graph of pβˆ’1p^{-1} is a reflection of the graph of pp across the line y=xy=x. βœ…
B.The graph of pβˆ’1p^{-1} is a translation of the graph of pp by 2 units up.
C.The inverse does not exist because decreasing functions fail the horizontal line test.
D.The inverse will be increasing.
πŸ’‘ Difficulty: medium | βœ… Correct: A

πŸ“– Explanation: When a function is one‑to‑one, its inverse exists and is obtained by reflecting each point (a,b)(a,b) to (b,a)(b,a). This geometric operation is precisely a reflection across the line y=xy=x. The statement about translation or monotonic direction is incorrect; the correct relationship is the reflection.

Q6. Let f(x)=x3f(x)=x^{3} and g(x)=x3g(x)=\sqrt[3]{x}. Which of the following statements is accurate?

A.Both ff and gg are decreasing, and gg is the inverse of ff.
B.Only ff is increasing; gg is not invertible.
C.Neither function passes the horizontal line test.
D.Both ff and gg are increasing, and gg is the inverse of ff. βœ…
πŸ’‘ Difficulty: medium | βœ… Correct: D

πŸ“– Explanation: Both functions have positive derivative for all real xx, so each is strictly increasing. Moreover, x3\sqrt[3]{x} undoes the cubing operation, making gg the exact inverse of ff. The other options either misstate monotonicity or ignore the inverse relationship.

Q7. Which point on the graph of y=f(x)=3xβˆ’2y = f(x) = 3x-2 corresponds to the point (5,13)(5,13) on the graph of its inverse fβˆ’1f^{-1}?

A.-135 βœ…
B.-513
C.(13,-5)
D.513
πŸ’‘ Difficulty: medium | βœ… Correct: A

πŸ“– Explanation: The inverse graph is obtained by swapping the coordinates of each point on the original graph. Therefore the point (5,13)(5,13) on fβˆ’1f^{-1} corresponds to (13,5)(13,5) on ff. This reflected point lies on the line y=3xβˆ’2y=3x-2, confirming the answer.

Q8. Let q(x)={x+1x≀02xβˆ’3x>0q(x)=\begin{cases} x+1 & x\le0 \\ 2x-3 & x>0 \end{cases}. Which of the following statements is true?

A.qq is strictly increasing on its entire domain, so it is invertible.
B.qq fails the horizontal line test because the two pieces intersect, so it is not invertible. βœ…
C.qq is decreasing on (βˆ’βˆž,0](-\infty,0] and increasing on (0,∞)(0,\infty), thus not one-to-one.
D.qq is strictly decreasing on its entire domain, so it is invertible.
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: The left branch yields values ≀1\le1 while the right branch starts at βˆ’3-3 and quickly exceeds those values, causing the same output to occur for different inputs (e.g., βˆ’1-1 and 1.51.5 both give 0). Hence the function is not one‑to‑one and fails the horizontal line test.

Q9. If ff is strictly increasing and invertible, what is the result of the composition f(fβˆ’1(x))f\bigl(f^{-1}(x)\bigr) for any xx in the range of ff?

A.It equals f(x)f(x).
B.It equals fβˆ’1(x)f^{-1}(x).
C.It equals xx. βœ…
D.It is undefined.
πŸ’‘ Difficulty: medium | βœ… Correct: C

πŸ“– Explanation: By definition of an inverse, applying ff after fβˆ’1f^{-1} returns the original argument: f(fβˆ’1(x))=xf(f^{-1}(x))=x for every xx in the range of ff. This identity holds regardless of monotonicity, making option C the correct choice.

Q10. Let hh be defined implicitly by x3+y3=6x^{3}+y^{3}=6. On the interval where yy is a function of xx, which of the following statements is true about hh and its inverse?

A.hh is decreasing, and its inverse is also decreasing. βœ…
B.hh is increasing, and its inverse is decreasing.
C.hh is decreasing, and its inverse is increasing.
D.hh is increasing, and its inverse is increasing.
πŸ’‘ Difficulty: hard | βœ… Correct: A

πŸ“– Explanation: Solving for yy gives y=(6βˆ’x3)1/3y=(6-x^{3})^{1/3}. Differentiating yields dy/dx=βˆ’(x2)/(y2)dy/dx=-(x^{2})/(y^{2}), which is negative wherever defined, so hh is strictly decreasing. The inverse of a decreasing one‑to‑one function is also decreasing, confirming option A.

Q11. Consider f(x)=1xf(x)=\frac{1}{x} with domain xβ‰ 0x\neq0. Which of the following correctly describes the relationship between the graph of ff and its inverse fβˆ’1f^{-1}?

A.The graphs are identical because ff equals its own inverse. βœ…
B.The graph of fβˆ’1f^{-1} is a vertical shift of the graph of ff.
C.The graph of fβˆ’1f^{-1} is a reflection of the graph of ff across the x‑axis.
D.The graph of fβˆ’1f^{-1} does not exist because ff is not one‑to‑one.
πŸ’‘ Difficulty: hard | βœ… Correct: A

πŸ“– Explanation: For f(x)=1/xf(x)=1/x, swapping xx and yy yields the same equation y=1/xy=1/x; thus ff is its own inverse. Consequently, the two graphs coincide, making option A correct. The other statements mischaracterize the symmetry or claim non‑existence.

Q12. Which statement best synthesizes the connection between monotonicity, the horizontal line test, and invertibility for a continuous function ff on R\mathbb{R}?

A.If ff is monotonic (strictly increasing or decreasing), then every horizontal line intersects its graph at most once, guaranteeing the existence of a unique inverse function. βœ…
B.Monotonicity guarantees a function passes the vertical line test, which ensures invertibility.
C.A function that fails the horizontal line test can still be invertible if it is piecewise monotonic.
D.The horizontal line test is irrelevant for continuous functions; only differentiability matters.
πŸ’‘ Difficulty: hard | βœ… Correct: A

πŸ“– Explanation: A strictly monotonic continuous function never takes the same value twice, so any horizontal line meets its graph at most once. This satisfies the horizontal line test, which is the precise criterion for the existence of a well‑defined inverse. The other options confuse different tests or ignore the key condition.

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