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πŸ“ Exponential functions properties and graphs (12 MCQs)

πŸ“– From Calculus β€’ 1. Basics before calculus β€’ 12 questions available

What is Exponential functions properties and graphs?

Definition:
Exponential functions are of the form f(x)=axf(x) = a^x with a>0,a≠1a>0, a \neq 1, having properties: a0=1a^0 = 1, ax+y=axaya^{x+y} = a^x a^y, increasing if a>1a>1, decreasing if 0<a<10<a<1, and with horizontal asymptote y=0y=0.

Example:
f(x)=2xf(x)=2^x passes through (0,1), (1,2), (2,4), and is increasing; g(x)=(1/2)xg(x)=(1/2)^x is decreasing but also passes through (0,1).

Reason:
Exponential functions model growth/decay in populations, finance, and physics, with graphs that show rapid change, making them indispensable in applied mathematics.

4
Easy
5
Medium
3
Hard

πŸ“ All Exponential functions properties and graphs MCQs

Q1. If b2=9b^2 = 9 for an exponential function f(x)=bxf(x)=b^x with b>0b>0, what is f(βˆ’3)f(-3)?

A.127\frac{1}{27} βœ…
B.27
C.19\frac{1}{9}
D.9
πŸ’‘ Difficulty: easy | βœ… Correct: A

πŸ“– Explanation: Since b2=9b^2=9 gives b=3b=3. The value at βˆ’3-3 is bβˆ’3=3βˆ’3=1/27b^{-3}=3^{-3}=1/27. The other options correspond to incorrect manipulations of the exponent or base. Therefore the correct choice is 127\frac{1}{27}.

Q2. Reflecting the graph of y=(12)xy=(\tfrac12)^x about the y‑axis yields which function, and how does its growth for positive xx compare to the original?

A.y=(12)βˆ’xy=(\tfrac12)^{-x}
B.y=2xy=2^{x} βœ…
C.y=(12)xy=(\tfrac12)^{x}
D.y=2βˆ’xy=2^{-x}
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: Replacing xx by βˆ’x-x gives (12)βˆ’x=2x(\tfrac12)^{-x}=2^{x}. The new function 2x2^{x} increases as xx increases, whereas the original (12)x(\tfrac12)^{x} decreases. Hence the reflected graph grows faster for positive xx. The other choices either leave the function unchanged or give a decreasing version.

Q3. For the exponential function f(x)=bxf(x)=b^{x} with b=3b=3, what is the horizontal asymptote of its graph?

A.y=1y=1
B.y=3y=3
C.y=0y=0 βœ…
D.y=∞y=\infty
πŸ’‘ Difficulty: easy | βœ… Correct: C

πŸ“– Explanation: Exponential graphs of the form bxb^{x} approach zero as xβ†’βˆ’βˆžx\to -\infty and never cross the x‑axis, making y=0y=0 the horizontal asymptote regardless of the base bb (provided b>0b>0 and bβ‰ 1b\neq1). The other options describe lines that are not asymptotes for this function.

Q4. The point (4,16)(4,16) lies on the graph of y=bxy=b^{x}. What is the value of the base bb?

A.4
B.16
C.sqrt2\\sqrt{2}
D.2 βœ…
πŸ’‘ Difficulty: easy | βœ… Correct: D

πŸ“– Explanation: Substituting the point gives b4=16b^{4}=16. Taking the fourth root yields b=161/4=2b=16^{1/4}=2. The other options either misinterpret the exponent or give incorrect roots. Thus the base is 22.

Q5. If an exponential function q(x)=bxq(x)=b^{x} satisfies q(βˆ’1)=0.5q(-1)=0.5, what is the base bb?

A.0.5
B.2 βœ…
C.12\tfrac12
D.4
πŸ’‘ Difficulty: easy | βœ… Correct: B

πŸ“– Explanation: The equation bβˆ’1=0.5b^{-1}=0.5 implies 1/b=0.51/b=0.5, so b=2b=2. Option B correctly reflects this value. Options A and C are the reciprocals, and D is unrelated.

Q6. Which statement correctly describes the relative growth of y=2xy=2^{x} and y=3xy=3^{x} for x>0x>0?

A.2x2^{x} grows faster than 3x3^{x}
B.3x3^{x} grows faster than 2x2^{x} βœ…
C.Both grow at the same rate
D.Both decrease as xx increases
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: Because the base 3 is larger than the base 2, the function 3x3^{x} increases more rapidly for positive xx. This is evident from comparing values such as 22=42^{2}=4 versus 32=93^{2}=9. The other options either reverse the relationship or incorrectly claim decreasing behavior.

Q7. Evaluate \\\displaystyle\\lim_{x\\to\\infty}\\left(\\tfrac12\\right)^{x}\.

A.1
B.\\\infty\
C.\-\\infty\
D.0 βœ…
πŸ’‘ Difficulty: medium | βœ… Correct: D

πŸ“– Explanation: The base \\\tfrac12\ lies between 0 and 1, so raising it to larger and larger exponents drives the value toward zero. Formally, \\\left(\\tfrac12\\right)^{x}=e^{x\\ln(\\tfrac12)}\ with \\\ln(\\tfrac12)<0\, yielding a limit of 0 as \x\\to\\infty\. The other choices misinterpret the behavior of a decaying exponential.

Q8. Which expression represents a vertical stretch of the graph of \y=b^{x}\ by a factor of 3?

A.y=b3xy=b^{3x}
B.y=(3b)xy=(3b)^{x} βœ…
C.y=3,bxy=3\\,b^{x}
D.y=bx+3y=b^{x+3}
πŸ’‘ Difficulty: medium | βœ… Correct: B

πŸ“– Explanation: Multiplying the entire function by 3 scales every output value by 3, which is a vertical stretch. The expression \3\\,b^{x}\ captures this effect. Options A and D change the exponent, altering the shape differently, while option B changes the base, also producing a different graph.

Q9. Replacing \x\ by \x-2\ in the equation \y=b^{x}\ results in which transformation of the graph?

A.Shift right by 2 units βœ…
B.Shift left by 2 units
C.Shift up by 2 units
D.Shift down by 2 units
πŸ’‘ Difficulty: hard | βœ… Correct: A

πŸ“– Explanation: The substitution \x\\rightarrow x-2\ moves every point of the original graph two units to the right because the function now reaches the same output value at an \x\ that is two larger than before. Horizontal translations affect the input variable, not the output, so the vertical shift options are incorrect.

Q10. Let \f(x)=b^{x}\ and \g(x)=c^{x}\ with \b>c>1\. Which inequality correctly compares their derivatives at \x=0\?

A.f&#039;(0)<g&#039;(0)
B.f&#039;(0)>g&#039;(0) βœ…
C.f&#039;(0)=g&#039;(0)
D.Cannot be determined without specific values
πŸ’‘ Difficulty: hard | βœ… Correct: B

πŸ“– Explanation: The derivative of \b^{x}\ is \\\ln(b)\\,b^{x}\; at \x=0\ this simplifies to \\\ln(b)\. Since \b>c\ and the natural logarithm is increasing, \\\ln(b)>\\ln(c)\. Therefore \f&#039;(0)>\\!g&#039;(0)\. The other options either reverse the inequality or claim equality without justification.

Q11. In the decay model \N(t)=N_{0}\\left(\\tfrac12\\right)^{t/5}\, what is the half‑life of the quantity?

A.2.5
B.10
C.1
D.5 βœ…
πŸ’‘ Difficulty: medium | βœ… Correct: D

πŸ“– Explanation: The expression \\\left(\\tfrac12\\right)^{t/5}\ indicates that every increase of 5 time units halves the quantity. Therefore the half‑life, the time required for the amount to reduce to one‑half its initial value, is 5 units. The other numbers correspond to different intervals but not the half‑life.

Q12. Solve for \x\ in the equation \4^{x}=8\.

A.2
B.0.5
C.1.5 βœ…
D.3
πŸ’‘ Difficulty: hard | βœ… Correct: C

πŸ“– Explanation: Rewrite both sides with base 2: \4^{x}=(2^{2})^{x}=2^{2x}\ and \8=2^{3}\. Equating exponents gives \2x=3\, so \x=\\tfrac{3}{2}=1.5\. Option C matches this value; the other options arise from incorrect exponent handling.

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